Question

我有一份职业清单，希望将它们与更大类别的职业相匹配。为此，我有一个表格，其中包含模式列表和匹配的职业类别。例如，

REGEX                               SuperCategory
cleaner                             Cleaners
(police)|(paramedic)|(emergency)    Emergency services
(manager)|(director)|(executive)    Management

structure(list(REGEX = c("cleaner", "(police)|(paramedic)|(emergency)"
), SuperCategory = c("Cleaners", NA)), class = c("tbl_df", "tbl", 
"data.frame"), row.names = c(NA, -2L), .Names = c("REGEX", "SuperCategory"
))

我想在另一个数据框架中创建一个新列，这是SuperCategory的元素，其中匹配相应行的REGEX模式。

我现在正在做的是一系列ifelse语句与grepl的结合。

df %>%
  mutate(SuperOccupation = ifelse(grepl(regex_decoder$REGEX[1], Occupation1, ignore.case=TRUE), 
                                  regex_decoder$SuperCategory[1],
                                  ifelse(grepl(regex_decoder$REGEX[2], 
                                               Occupation1, 
                                               ignore.case=TRUE), 
                                         regex_decoder$SuperCategory[2], 
                                         ifelse(grepl(regex_decoder$REGEX[3],
                                                      Occupation1,
                                                      ignore.case=TRUE),
                                                regex_decoder$SuperCategory[3],
                                                NA_character_))))

但我必须继续为我的桌子长度筑巢。有没有办法加入＆＃34;通过正则表达式？

匹配正则表达式表

0 个答案: