Question

我有一个红色表“人”，其中特定列的数据类似于此

[{"attributeName":"name","attributeMetadata":null,"attributeValue":"KitchenAid - 7-Speed Hand Mixer - White","attributeImageType":"PRODUCT","attributeStatusCodes":[]},
{"attributeName":"title","attributeMetadata":null,"attributeValue":"KitchenAid","attributeImageType":"PRODUCT","attributeStatusCodes":[]},

{"attributeName":"address","attributeMetadata":null,"attributeValue":"address","attributeImageType":"PRODUCT","attributeStatusCodes":[]},

{"attributeName":"PIN CODE","attributeMetadata":null,"attributeValue":"32110","attributeImageType":"IMG","attributeStatusCodes":[]}]

我想只提取包含PIN CODE的字典/ json / substring（见下文）

{"attributeName":"PIN CODE","attributeMetadata":null,"attributeValue":"32110","attributeImageType":"IMG","attributeStatusCodes":[]}

我尝试了以下查询，它发出以下错误

select distinct regexp_substr(attributes,'.*({.*?"attributeName":"PIN CODE".*?}).*') from person ;

ERROR:  Invalid content of repeat range
DETAIL:  
  -----------------------------------------------
  error:  Invalid content of repeat range
  code:      8002
  context:   T_regexp_init
  query:     528401
  location:  funcs_expr.cpp:130
  process:   query2_40 [pid=12603]
  -----------------------------------------------

我猜问题是因为单个列中有多个attributeName而发生的。是他们达到预期结果的方法。

Answer 1

我不确定我是否理解正确，但您可以尝试使用LIKE：

    select * from person where attributes LIKE '%"attributeName":"PIN CODE"%';

redshift数据库中的子字符串匹配

1 个答案: