Question

我有一个JSON对象：

[{"box":1,"parent":[],"child":[{"boxId":2},{"boxId":3}]},{"box":2,"parent":[{"boxId":1}],"child":[]}]

我想删除带有boxId = 2的"child":[{"boxId":2}。我正在使用，映射函数如下：

Arr.map(function (box) {
  box.child.map(function (p) {
    p.remove();
  });
});

它不起作用。我收到错误。

。删除不是函数`

有什么方法可以删除特定元素吗？

修改

例如：我想从子项中删除{"boxId":2}，生成的JSON应该是：

[{"box":1,"parent":[],"child":[{"boxId":3}]},{"box":2,"parent":[{"boxId":1}],"child":[]}]

Answer 1

将Array.prototype.map()与Array.prototype.forEach()

一起使用

var arr = [{"box":1,"parent":[],"child":[{"boxId":2},{"boxId":3}]},{"box":2,"parent":[{"boxId":1}],"child":[]}];

// Loop over main array
arr.map(function(e) {
  
  // Get the child element array and iterate over it
  return e.child.forEach(function(c, i) {
    
    // If box to remove found
    if (c.boxId === 2) {
      // Remove the element from main array element
      delete e.child.splice(i, 1);
    }
  });
});

console.log(arr);
document.getElementById('output').innerHTML = JSON.stringify(arr, 0, 4);

<pre id="output"></pre>

Answer 2

试试这个

import json                                                                                         

my_list = [['apple',{'john':3,'anna':4,'kitty':6}],['pear',{'john':4,'anna':3,'kitty':3}]]

name_list = [item[1] for item in my_list]  # [{'john': 3, 'kitty': 6, 'anna': 4}, {'john': 4, 'kitty
names = name_list[0].keys()  # ['john', 'kitty', 'anna']                       
name_values = [[item[key] for item in name_list] for key in names]  # [[3, 4], [6, 3], [4, 3]]
result = {                                                                     
    'key': [item[0] for item in my_list],                                      
    'value': [                                                                 
        {'name': name, 'value': value}                                         
        for (name, value) in zip(names, name_values)                           
    ]                                                                          
}                                                                              

print(json.dumps(result, indent=4))

JSFIDDLE

使用.map函数

2 个答案: