Question

目前我想在用户登录系统时从两个表中获取两个不同的数据。权利表是“user”，“user_staff”和“user_group”。但是，当用户输入其用户名和密码并提交时，提示 “致命错误：在C：\ xampp \ htdocs \ auditsystem \ index.php中的非对象上调用成员函数fetch_array（）第26行“

以下是代码：

if($username!= "" && $password != "")
{
//INNER JOIN user_group_module_role ON user.user_group_module_role_id = user_group_module_role.id
    $result =  $db->query("SELECT * FROM user 
                            INNER JOIN user_staff ON user.user_staff_id = user_staff.id
                            WHERE username = '$username' AND password = '$password'"); 



    if($result->num_rows == 1)
    {
        $validate = $result->fetch_assoc();

        $query1 = "SELECT * FROM usergroup WHERE id = $validate[user_group_id]";
        $result1 = $db->query($query1);
        $row1 = $result1->fetch_array();
        //change here for the authority 
        $_SESSION['user_staff'] = $validate['displayname'];
        $_SESSION['usergroup'] = $row1['user_group_type'];
        echo "<script language='javascript'>window.location='panel.php'</script>"; 
    }
    else
    {
        echo "<script>alert('Sorry, wrong username and password please check.')</script>";
    }
}

Answer 1

您的查询格式错误且失败。这使得$ result1为null / false。您的查询也容易受到SQL注入的攻击！

if($username!= "" && $password != ""){
//INNER JOIN user_group_module_role ON user.user_group_module_role_id = user_group_module_role.id
    $result =  $db->query("SELECT * FROM user INNER JOIN user_staff ON user.user_staff_id = user_staff.id WHERE username = '$username' AND password = '$password'"); 
    if($result->num_rows == 1){
        $validate = $result->fetch_assoc();
        $query1 = "SELECT * FROM usergroup WHERE id = {$validate['user_group_id']}";
        if($result1 = $db->query($query1)){
            $row1 = $result1->fetch_array();
            //change here for the authority 
            $_SESSION['user_staff'] = $validate['displayname'];
            $_SESSION['usergroup'] = $row1['user_group_type'];
            echo "<script language='javascript'>window.location='panel.php'</script>"; 
        } else {
            echo "<script language='javascript'>alert('SQL Error.');</script>";
        }
    } else {
        echo "<script>alert('Sorry, wrong username and password please check.')</script>";
    }
}

从$ _SESSION PHP获取多个表中的数据

1 个答案: