Question

好吧所以我正在创建一个与cpu战斗的程序，但是每次它首先输入一个小姐然后是一个致命的错误，我会破坏我的代码，这样你们就可以更容易地帮忙了。

进口：

 var result = (from c in _db.rEmails
                where c.Email.Contains(id)
            select c.ALIAS_NAME)
             .FirstOrDefault();

设置整数和确定命中类型的rng：

import javax.swing.JOptionPane;
import java.util.Random;

命中的类型和它们应分别做什么：

int life = 100; //Your life
int life2 = 100; //Enemy life
Random chance = new Random();
int rand = chance.nextInt(1)+100;

我愿意尝试任何事情，我迫切需要完成这些人，谢谢你的帮助。

Answer 1

当您设置int rand = chance.nextInt(1)+100时，您将获得0到1之间的随机整数，然后向其中添加100，因此rand将为100或101.这会导致{{1}每次都要执行if / else语句的块。

我相信你想要的是//Fatality。

此外，您在if语句中的比较不正确。您需要在每个if语句中切换chance.nextInt(100)+1和<。

编辑：正如@KonstantinosChalkias所指出的那样，使用if (rand <= 20 ){//Miss JOptionPane.showMessageDialog(null, "You have missed your opponent like a fool.\nYour Opponent has "+life2+" remaining."); } else if (rand >= 21 && rand <= 34){//Wiff int Wiff = chance.nextInt(10)+1; life = life-Wiff; JOptionPane.showMessageDialog(null, "You have stubbed your toe. Idiot.\nYou have "+life+" remaining."+Wiff); } else if (rand >= 35 && rand <= 74){//Regular Hit int regHit = chance.nextInt(20)+1; life2 = life2-regHit; JOptionPane.showMessageDialog(null, "You have hit your opponent!"+regHit); } else if (rand >= 75 && rand <= 90){//CritHit int critHit = chance.nextInt(40)+1; life2 = life2-critHit; JOptionPane.showMessageDialog(null, "You have dealt critical damage!"+critHit); } else {//Fatality. JOptionPane.showMessageDialog(null, "Fatality!\nYou stabbed your opponent in the foot,\ndrug your knife throught" + "his belly,\nand impaled his head on your knife!"); System.exit(0); }，您可以完全删除else if部分逻辑。

&&

Answer 2

刚刚加入安德鲁的回答，

似乎所有'命中'的if语句实际上都是不可能的

if (rand <= 21 && rand >= 34){//Wiff
    int Wiff = chance.nextInt(10)+1;
    life = life-Wiff;
    JOptionPane.showMessageDialog(null, "You have stubbed your toe. Idiot.\nYou have "+life+" remaining."+Wiff);
}

上述情况永远不会成立，因为rand不能同时小于21且大于34，你确定你不是要代替OR语句吗？

如下所示：

if (rand <= 21 || rand >= 34){//Wiff
    int Wiff = chance.nextInt(10)+1;
    life = life-Wiff;
    JOptionPane.showMessageDialog(null, "You have stubbed your toe. Idiot.\nYou have "+life+" remaining."+Wiff);
}

或者你的意思是：

if (rand >= 21 && rand <= 34){//Wiff
    int Wiff = chance.nextInt(10)+1;
    life = life-Wiff;
    JOptionPane.showMessageDialog(null, "You have stubbed your toe. Idiot.\nYou have "+life+" remaining."+Wiff);
}

哪个会更有意义

Answer 3

正如已经指出的那样，您的if语句重叠或逻辑错误。我想你想给出一些概率让我们说20％的人错过目标，15％的人“踩到你的脚趾”等等。实际上，您可以使用if-else语句

将代码简化为不需要&&

if (rand <= 20 ){//Miss 20%
    ...
} else if (rand <= 35){//Wiff 15%
    ...
} else if (...){//for each of the following cases
    ...
} else {//Fatality
    ...
}

RNG游戏在制作中，需要帮助确定命中的类型

3 个答案: