Question

import java.io.*;
import java.util.*;

public class Hellno {
    public static void main(String[] args) {
        try {
            Scanner s = new Scanner(new File("words.txt"));
            findBiggest(s);
            System.out.println(findBiggest(s));
        } catch (IOException e) {
            System.out.println("Can't find that file");
        }
    }

    public static String findBiggest(Scanner scan) {
        int count0 = 0;
        int count1 = 0;
        String srs = "";

        while (scan.hasNext()) { //how do i make this the longest?
            String nsrs = scan.next();
            count0 = nsrs.length();

            if (count0 > count1) { // if the new length is bigger than what was solidified
                count1 = count0; //new solidification of number
                count0 = 0; // count becomes 0  to start again
                srs = nsrs; // nsrs has been solidified as the new biggest String
            }

            else if (count0 <= count1) { // if the new length is smaller than what was solidified
                count0 = 0; //then we start again with dummyCount = 0;
             }   
        }
        return srs;}}

我正在尝试从文本文件中读取，找出最长的字符串并返回该字符串。但是，这个编码忽略了所有while（）并且似乎跳转到返回srs。为什么？

Answer 1

您在同一个findBiggest上拨打Scanner两次。第一次调用可能找到了最大的单词并将其返回，但它被忽略了。第二个调用找不到任何单词，while循环没有迭代。

只需拨打findBiggest一次。

Scanner s = new Scanner(new File("words.txt"));
System.out.println(findBiggest(s));

Answer 2

需要在扫描仪上设置分隔符

  Scanner s = new Scanner(input).useDelimiter(System.getProperty("line.separator"));

Java初学者：忽略While循环

2 个答案: