Question

我正在尝试从数据库中返回最后10条记录并将其显示在网页上。我下面的代码只返回一条记录，有谁知道我哪里出错了？我稍后会用桌子整理它，目前我只需要最后10条记录。

表的名称是“devel”，列名是：id，STATION，REASON_CODE，ERROR，WEEK，COMMENT，DOWNTIME，DATE

$dbc = mysqli_connect(‘xxxx’, ‘xxxx’, 'xxxx', ‘xxxx’)
    or die('Error connecting to MySQL server.');

$query = "SELECT * FROM devel ORDER BY id DESC LIMIT 10";

$result = mysqli_query($dbc, $query)
    or die('Error querying database.');

while($record = mysqli_fetch_array($result)){
echo $record['id']. " " .$record['STATION'] . " " . $record['REASON_CODE'] . " " . $record['ERROR']. " " .$record['WEEK'] . " " .$record['COMMENT'] . " "    .$record['DOWNTIME'] . " " .$record['DATE'];
echo "<br /";
}

Answer 1

试试这个

$dbc = mysqli_connect(‘xxxx’, ‘xxxx’, 'xxxx', ‘xxxx’)
    or die('Error connecting to MySQL server.');
$query = "SELECT * FROM devel ORDER BY id DESC LIMIT 10"; 
$result = mysqli_query($dbc, $query)
    or die('Error querying database.');
echo "<table><tr>
                 <th>Id</th>
                 <th>STATION</th>
                 <th>REASON_CODE</th>
                 <th>ERROR</th>
                 <th>WEEK</th>
                 <th>COMMENT</th>
                 <th>DOWNTIME</th>
                 <th>DATE</th>
            </tr>";
while($record = mysqli_fetch_assoc($result)){
 echo "<tr>"; 
 echo "<td>".$record['id']."</td>";
 echo "<td>".$record['STATION']."</td>";
 echo "<td>".$record['REASON_CODE']."</td>";
 echo "<td>".$record['ERROR']."</td>";
 echo "<td>".$record['WEEK']."</td>";
 echo "<td> ".$record['COMMENT']."</td>";
 echo "<td> ".$record['DOWNTIME']."</td>";
 echo "<td> ".$record['DATE']."</td>";
 echo "</tr>";  
}
 echo "</table>";

在网页上显示MySql记录，PHP

1 个答案: