Question

我有一个由两个表组成的视图表（让我们称之为view_table）（让我们称之为table_1＆amp; table_2）。我们假设table_1在引用表fk_field的字段fk_table上有一个外键。

是否有直接查询view_table以获取字段fk_table的参考表fk_field？

我是用PHP做的，所以我想做的事情就是：

从VIEW_DEFINITION解析INFORMATION_SCHEMA.VIEWS字段，以获取构成view_table的表格列表（例如table_1＆amp; table_2）
对于其中每个表格，请使用this method获取fk_table

是否有更好（即更简单）的方法？

修改

在这种情况下的视图定义，字段Container是一个引用名为Containers的表的外键：

CREATE 
    ALGORITHM = UNDEFINED 
    DEFINER = `root`@`localhost` 
    SQL SECURITY DEFINER
VIEW `LIMS_dev`.`DerivativeView` AS
    SELECT 
        `a`.`Derivative` AS `Derivative`,
        `a`.`Container` AS `Container`,
        `a`.`DerivativeTypeID` AS `DerivativeTypeID`,
        `a`.`StorageFormatID` AS `StorageFormatID`,
        `a`.`SourceSample` AS `SourceSample`,
        `a`.`Parent` AS `Parent`,
        `a`.`Date` AS `DerivativeDate`,
        `a`.`Active` AS `SampleActive`,
        `a`.`User` AS `User`,
        `a`.`Notes` AS `Notes`,
        `b`.`Shelf` AS `Shelf`,
        `b`.`Rack` AS `Rack`,
        `b`.`FreezerID` AS `FreezerID`,
        `b`.`Active` AS `BoxActive`,
        `b`.`Date` AS `ContainerDate`
    FROM
        (`LIMS_dev`.`Derivatives` `a`
        LEFT JOIN `LIMS_dev`.`Containers` `b` ON ((`a`.`Container` = `b`.`Container`)))

MySQL从视图表中获取外键

0 个答案: