我需要创建24位集。 第一个(0)位必须由bool设置。 和其他(1 - 23)我需要从uint32值
复制第一位是否可以使用dynamic_bitset执行此操作?
我的代码我试过但错了:
class B
答案 0 :(得分:1)
左转:
DataType bs(24, intValue);
bs <<= 1;
bs.set(0, boolValue);
<强> Live On Coliru 强>
#include <boost/dynamic_bitset.hpp>
#include <iostream>
typedef boost::dynamic_bitset<unsigned char> DataType;
int main() {
using namespace std; // for readability on SO
cout << hex << showbase;
uint32_t intValue = 0x666;
cout << "input: " << intValue;
DataType bs(24, intValue);
cout << "\n#1: " << bs << " " << bs.to_ulong();
bs <<= 1;
cout << "\n#2: " << bs << " " << bs.to_ulong();
bs.set(0, true);
cout << "\n#3: " << bs << " " << bs.to_ulong();
}
打印:
input: 0x666
#1: 000000000000011001100110 0x666
#2: 000000000000110011001100 0xccc
#3: 000000000000110011001101 0xccd
答案 1 :(得分:0)
所以,我设法以这种方式完成,没有增强位集:
uint32_t buffer(0xAAAAAAAA);
buffer = buffer << 1;
buffer |= true << 0;
unsigned char newRecord[3];
newRecord[0] = buffer;
newRecord[1] = buffer << 8;
newRecord[2] = buffer << 16;