Question

我试图从另一个表中选择行计数，即使它是空的，所以如果它是空的，它只显示数字0但仍然选择主表的行。 / p>

这是我的sql：

SELECT training.*, 
    count(distinct training_transactions.training_transaction_course) as completed_training_payments 
    FROM training
    INNER JOIN training_transactions
         ON training.course_id = training_transactions.training_transaction_course
    WHERE course_main = ?
        AND course_enabled = 'enabled'

培训表：

CREATE TABLE IF NOT EXISTS `training` (
  `course_id` int(11) NOT NULL,
  `course_user` int(11) NOT NULL,
  `course_main` int(11) NOT NULL,
  `course_type` varchar(255) NOT NULL,
  `course_name` varchar(255) NOT NULL,
  `course_description` text NOT NULL,
  `course_location` varchar(255) NOT NULL,
  `course_duration` varchar(255) NOT NULL,
  `course_fitness_type` varchar(255) NOT NULL,
  `course_instructor_name` varchar(255) NOT NULL,
  `course_price` int(15) NOT NULL,
  `course_start_date` date NOT NULL,
  `course_max_attendees` int(8) NOT NULL,
  `course_accommodation` varchar(255) NOT NULL,
  `course_accommodation_price` varchar(255) NOT NULL,
  `course_status` varchar(50) NOT NULL,
  `course_enabled` varchar(10) NOT NULL DEFAULT 'enabled',
  `course_location_name` varchar(255) NOT NULL,
  `course_location_street` varchar(255) NOT NULL,
  `course_location_town` varchar(255) NOT NULL,
  `course_location_county` varchar(255) NOT NULL,
  `course_location_postcode` varchar(255) NOT NULL,
  `course_location_country` varchar(255) NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1;

--
-- Dumping data for table `training`
--

INSERT INTO `training` (`course_id`, `course_user`, `course_main`, `course_type`, `course_name`, `course_description`, `course_location`, `course_duration`, `course_fitness_type`, `course_instructor_name`, `course_price`, `course_start_date`, `course_max_attendees`, `course_accommodation`, `course_accommodation_price`, `course_status`, `course_enabled`, `course_location_name`, `course_location_street`, `course_location_town`, `course_location_county`, `course_location_postcode`, `course_location_country`) VALUES
(1, 3, 4, 'Health & Safety', 'lol', 'This is just a short description, this can be editted', '1', '13', 'lol', 'lol', 5, '1991-02-12', 4, '1', '4', 'live', 'enabled', '', '', '', '', '', 'United Kingdom'),
(2, 3, 4, 'Working at Height', 'lol', '', '1', '11', 'jkjkj', 'kjkjkj', 124, '0000-00-00', 6, '0', '', 'live', 'enabled', '', '123', '123', '123', 'WN8', 'United Kingdom'),
(3, 3, 4, 'Working at Height', 'lol', '', '1', '11', 'jkjkj', 'kjkjkj', 124, '0000-00-00', 6, '0', '', 'live', 'enabled', '', '123', '123', '123', 'WN8', 'United Kingdom');

training_transactions

CREATE TABLE IF NOT EXISTS `training_transactions` (
  `training_transaction_id` int(11) NOT NULL,
  `training_transaction_user` int(11) NOT NULL,
  `training_transaction_course` int(11) NOT NULL,
  `training_transaction_status` varchar(50) NOT NULL DEFAULT 'pending',
  `training_transaction_payment_status` varchar(50) NOT NULL,
  `training_transaction_cost` int(11) NOT NULL,
  `training_transaction_enabled` varchar(50) NOT NULL DEFAULT 'enabled',
  `training_transaction_date` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `training_transaction_billing_name` varchar(250) NOT NULL,
  `training_transaction_billing_address1` varchar(250) NOT NULL,
  `training_transaction_billing_address2` varchar(250) NOT NULL,
  `training_transaction_billing_city` varchar(250) NOT NULL,
  `training_transaction_billing_state` varchar(250) NOT NULL,
  `training_transaction_billing_postcode` varchar(250) NOT NULL,
  `training_transaction_billing_country` varchar(250) NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=latin1;

--
-- Dumping data for table `training_transactions`
--

INSERT INTO `training_transactions` (`training_transaction_id`, `training_transaction_user`, `training_transaction_course`, `training_transaction_status`, `training_transaction_payment_status`, `training_transaction_cost`, `training_transaction_enabled`, `training_transaction_date`, `training_transaction_billing_name`, `training_transaction_billing_address1`, `training_transaction_billing_address2`, `training_transaction_billing_city`, `training_transaction_billing_state`, `training_transaction_billing_postcode`, `training_transaction_billing_country`) VALUES
(1, 3, 1, 'pending', 'complete', 0, 'enabled', '2015-09-17 14:02:29', *removed my address*);

目前只显示ID为1的培训课程，因为交易中存在一行，如果在training_transactions中没有id匹配，我怎样才能显示所有培训？

Answer 1

INNER JOIN仅选择两个表中包含连接键的记录的记录。

使用LEFT JOIN / RIGHT JOIN，可以选择一边不存在记录的选项;他们的字段值将为NULL（当计算时，它们应为零，但我并不完全确定）

Answer 2

使用LEFT JOIN而不是内部联接来列出联接左侧表中的所有记录，另外需要将count（）放在子查询中以获取训练表中的所有字段：

C runtime

Answer 3

有时使用子查询会更容易。试试这个：

SELECT training.*, 
    (SELECT COUNT(distinct training_transactions.training_transaction_course)
     FROM training_transactions
     WHERE training.course_id = training_transactions.training_transaction_course) AS completed_training_payments 
FROM training
WHERE training.course_main = ?
  AND training.course_enabled = 'enabled'

从另一个表中选择计数仅显示存在的一行

3 个答案: