Question

我有这个foreach：

  <?php foreach ($manufacturers as $key => $manufacturer) {


        if($manufacturer->virtuemart_manufacturercategories_id == 1){
            $lang = 'heb'; //Hebrew
        } else {
            $lang = 'eng'; //English
        }

        //add to letter list


         $letter = mb_substr($manufacturer->mf_name, 0, 1, 'UTF-8');
         ${'html_letters_'.$lang}[] = $letter;

      /*
        echo '<pre>';
        print_r($manufacturer);
        echo '</pre>';*/

        $link = JROUTE::_('index.php?option=com_virtuemart&view=category&virtuemart_manufacturer_id=' . $manufacturer->virtuemart_manufacturer_id);

        ${'html_manufacturers_'.$lang} .= '<div class="manufacturer" data-lang="'.$lang.'" data-letter="'.$letter.'"><a href="'.$link.'">';
        ?>
        <?php
        if ($manufacturer->images && ($show == 'image' or $show == 'all' )) {
            ${'html_manufacturers_'.$lang} .= $manufacturer->images[0]->displayMediaThumb('',false);
        }
        if ($show == 'text' or $show == 'all' ) {
            ${'html_manufacturers_'.$lang} .= '<div>'.$manufacturer->mf_name.'</div>';
        }
            ${'html_manufacturers_'.$lang} .= '</a>
        </div> <!-- /manufacturer -->';

        if ($col == $manufacturers_per_row){
            $col = 1;
        } else {
            $col++;
        }
    } 



    ?>

我如何检查我是否有超过2个相同的字母并取消所有其他字母，但保留一个。

信件的输出是：

AABCHKIUKP

我希望这会是：

ABCHKIUKP

我是怎么做到的？

编辑：我已经更新了所有的foreach代码。问题是，如果我有更多相同的起始字母名称EG：香气，空气循环取第一个字母A并预先他2次，我想只显示一个，如果有甚至10个相同的起始名称。

感谢。

Answer 1

当我理解你的时候......只需使用数组

<?php 
      $letters = array();
      foreach ($manufacturers as $key => $manufacturer) {
           ....
           $letter = mb_substr($manufacturer->mf_name, 0, 1, 'UTF-8');
           $letters[] = $letter;
      }
      $uni = array_unique($letters)
      echo implode('',$uni);

Answer 2

$s = 'AABCHKIUKP';

$letters = $letters = preg_split('/(?<!^)(?!$)/u', $s); //utf8
$prev_letter = '';
$temp = '';
foreach($letters as $key => $letter) {
    if (!($letter === $prev_letter)) {
        $temp .= $letter;
    }
    $prev_letter = $letter;
}
echo $temp;

结果：

ABCHKIUKP

有关将utf8字符串分解为数组的信息，您可以在此处的评论中找到mb_split。

Answer 3

要剥离仅相同的连续字符，您可以使用此字符：

function stripConsecutiveChars( $string ) {
    // creates an array with chars from the string
    $charArray = str_split( $string );

    // saves the last char thats on the new string
    $lastChar = "";

    // variable for the new string to return
    $returnString = "";

    foreach( $charArray as $char ) {
        if( $char === $lastChar ) continue;

        $lastChar = $char;// save current char
        $returnString .= $char;// concat current char to new string
    }

    return $returnString;
}

$string = "AABCHKIUKP";
echo stripConsecutiveChars( $string );

在您的示例中，您可以尝试这样做：

...
$letter = mb_substr( $manufacturer->mf_name, 0, 1, 'UTF-8' );
$lastLetter = end( ${'html_letters_' . $lang} );//point to last element in array
reset( ${'html_letters_' . $lang} );// reset the pointer
if( $letter === $lastLetter ) {
    // i guess you just want to continue?
    continue;
}
...

输出：

ABCHKIUKP

PHP里面的foreach问题

3 个答案: