Question

我有来自Android系统的String。我收到字符串，对应于php文件中的地址，并想检查此地址是否与我的数据库中的地址匹配。但是，我希望它能够按照用户输入的单词的顺序工作。

起初，我使用LIKE如下：

$address=preg_replace('#\s+#','%',$_POST['address']);
    $address='%'.$address.'%';
    echo $address;
    $list_business = $bdd->prepare('SELECT * FROM business WHERE address LIKE ? OR name_business LIKE ?'); 
    $list_business->execute(array($address,$address));

这实际上允许我获得结果，即使有些单词被省略。例如443 Street将匹配443 First Street。但如果用户输入id为First Street 443，它将不会返回任何内容。我在想Regex，但是它真的适应了这种问题吗？或者我应该每个单词使用一个不同的正则表达式？

Answer 1

您可能想看一下第三方搜索引擎，它们可以很容易地为您完成此任务。

按顺序查看SOLR，ElasticSearch和Sphinx。

你可以用Mysql的全文搜索来做到这一点，但上面的搜索引擎可以做得更好。

这是使用MySQL内置全文搜索的演示

mysql> show tables;
+----------------+
| Tables_in_test |
+----------------+
| sample         |
+----------------+
1 row in set (0.00 sec)

mysql> show create table test.sample;
+--------+--------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| Table  | Create Table                                                                                                                                                       |
+--------+--------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| sample | CREATE TABLE `sample` (
  `id` int(11) NOT NULL,
  `address` text,
  PRIMARY KEY (`id`),
  FULLTEXT KEY `ftext` (`address`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 |
+--------+--------------------------------------------------------------------------------------------------------------------------------------------------------------------+
1 row in set (0.00 sec)

mysql> select * from test.sample;
+----+-----------------------------------------+
| id | address                                 |
+----+-----------------------------------------+
|  1 | 345 Park Avenue New York, NY 10154-0102 |
|  2 | 610 Waring Ave Bronx, New York NY 10467 |
+----+-----------------------------------------+
2 rows in set (0.00 sec)

mysql> SELECT * FROM test.sample 
    -> WHERE match(`address`)
    -> against('+new +york +ave' IN BOOLEAN MODE);
+----+-----------------------------------------+
| id | address                                 |
+----+-----------------------------------------+
|  1 | 345 Park Avenue New York, NY 10154-0102 |
|  2 | 610 Waring Ave Bronx, New York NY 10467 |
+----+-----------------------------------------+
2 rows in set (0.00 sec)

mysql> SELECT * FROM test.sample
    -> WHERE match(`address`)
    -> against('+ny +park' IN BOOLEAN MODE);
+----+-----------------------------------------+
| id | address                                 |
+----+-----------------------------------------+
|  1 | 345 Park Avenue New York, NY 10154-0102 |
+----+-----------------------------------------+
1 row in set (0.00 sec)

mysql>

php - 从数据库中查找文本中的多个单词

1 个答案: