Question

像这样查询：

select [name],count(*) as [count], SUM(balance1) balance1,SUM(balance2) balance2
from mytbl
WHERE [date] between ... --some filters
GROUP BY [name]

查询结果是：

已编辑：

name   balance1    balance2  count
A1      10.00       12.00     10
A2      11.00       20.00     20
A3      9.00        5.00      30
BB1     5.00        2.00      45
BB2     1.00        0.00      50
CCC1    15.00       20.00     23

想要通过字母组成的组必须是：

name   balance1    balance2   count
A1      10.00       12.00      10
A2      11.00       20.00      20
A3      9.00        5.00       30
SUM     30.00       37.00      60
BB1     5.00        2.00       45
BB2     1.00        0.00       50
SUM     6.00        2.00       95
CCC1    15.00       20.00      23
SUM     15.00       20.00      23

已编辑： 示例数据：http://sqlfiddle.com/#!3/977f5/1

怎么做？

Answer 1

您可以使用grouping sets：

执行此操作

select coalesce(name, 'SUM') as name,
       count(*) as [count],
       SUM(balance1) as balance1, SUM(balance2) as balance2
from mytbl
where [date] between ... --some filters
group by grouping sets( (name, left(name, 1)), (left(name, 1)) );

（注意：这使用coalesce()的懒惰短手来识别＆＃34; SUM＆＃34;行。）

如何按不同名称的列对数据进行求和

1 个答案: