我有一个数组$array1
,其中包含不同数量的键和值对:
Array
(
[0] => Array
(
[ID] => 39
[title] => Apple
)
[1] => Array
(
[ID] => 40
[title] => Orange
)
)
和另一个数组$array2
:
Array
(
[0] => 273
[1] => 386
)
我希望得到这个:
Array
(
[0] => Array
(
[ID] => 39
[title] => Apple
[pages] => 273
)
[1] => Array
(
[ID] => 40
[title] => Orange
[pages] => 386
)
)
每个数组中的项目数相同且对应,因此,我们不需要检查这个,那么,如何合并它呢?
答案 0 :(得分:7)
如果要使用整数键合并,请使用array_replace_recursive
;如果希望仅合并字符串键,请使用array_merge_recursive
<?php
$a1 = array(
0 => array
(
"ID" => 39,
"title" => "Apple"
),
1 => array(
"ID" => 40,
"title" => "Orange"
)
);
$a2 = array(
0 => array
(
"pages" => 273,
"year" => 1981
),
1 => array(
"pages" => 386,
"year" => 1979
)
);
$a3 = array_replace_recursive($a1, $a2);
var_dump($a3);
结果:
array(2) {
[0] =>
array(4) {
'ID' =>
int(39)
'title' =>
string(5) "Apple"
'pages' =>
int(273)
'year' =>
int(1981)
}
[1] =>
array(4) {
'ID' =>
int(40)
'title' =>
string(6) "Orange"
'pages' =>
int(386)
'year' =>
int(1979)
}
}
回答更新的问题:
<?php
$a1 = array(
0 => array
(
"ID" => 39,
"title" => "Apple"
),
1 => array(
"ID" => 40,
"title" => "Orange"
)
);
$a2 = array(
0 => 31,
1 => 324
);
$defaultValue = 0;
foreach ($a1 as $key => $value) {
$a1[$key]['pages'] = isset($a2[$key]) ? $a2[$key] : $defaultValue;
}
var_dump($a1);
结果:
array(2) {
[0] =>
array(3) {
'ID' =>
int(39)
'title' =>
string(5) "Apple"
'pages' =>
int(31)
}
[1] =>
array(3) {
'ID' =>
int(40)
'title' =>
string(6) "Orange"
'pages' =>
int(324)
}
}
答案 1 :(得分:1)
试试这段代码: -
$newArray = array();
$i=0;
foreach($array1 as $value){
$newArray[$i] = $value;
$newArray[$i][] = $array2[$i];
$i++;
}
答案 2 :(得分:1)
以下是生成您正在寻找的输出的代码:
<?php
$list1 = array(array('id' => 39,'title' => 'Apple'),array('id' => 40,'title' => 'Orange'));
$list2 = array(array('pages' => 273,'year' => 1981),array('pages' => 386,'year' => 1979));
$newList = array();
$i=0;
foreach($list1 as $firstList){
foreach($list2 as $secondList){
$newList[$i] = array_merge($firstList, $secondList);
}
$i++;
}
echo"<pre>"; print_r($newList); echo"</pre>";
?>
输出:
答案 3 :(得分:0)
试试这个
array1[0][pages]=array2[0][pages];
array1[0][year]=array2[0][year];
array1[1][pages]=array2[1][pages];
array1[1][year]=array2[1][year];
答案 4 :(得分:0)
如果2个阵列的大小相同,你可以这样做
$arr1 = array(
array(
'ID' => 39,
'title' => 'Apple'
),
array(
'ID' => 40,
'title' => 'Orange'
)
);
$arr2 = array(
273,
386
);
$merged = array();
for ($i = 0; $i < count($arr1); $i++) {
$merged[] = array_merge($arr1[$i], array('pages' => $arr2[$i]));
}
var_dump($merged);
或者如果您不想要新阵列
for ($i = 0; $i < count($arr1); $i++) {
$arr1[$i]['pages'] = $arr2[$i];
}
答案 5 :(得分:0)
for($i=0; $i<count($array1); ++$i){
$array1[$i]['pages'] = $array2[$i];
}
var_dump($array1);
答案 6 :(得分:0)
$output = array();
array_walk( $array1, function( $v, $k ) use ( $array2, &$output ) {
$output[] = array_merge( $v, $array2[$k] );
});