Question

我的字符串包含\xXXXX和\uXXXX：

str = "\nDefault\nRouterRandom=\x9Db\u0012\xD3,\x92r\xFC o\u007F\x9B+\u0005I`\nWebInit=1\n"

我想删除内容：

"RouterRandom=\x9Db\u0012\xD3,\x92r\xFC o\u007F\x9B+\u0005I`\n"

如何匹配字符串或将其删除？我试过了：

content = str.sub(/RouterRandom=.*WebInit/, "")

它返回错误：

E:/Automation/experiment/ruby_test/string_test.rb:119:in `sub': invalid byte sequence in UTF-8 (ArgumentError)
from E:/Automation/experiment/ruby_test/string_test.rb:119:in `block in <top (required)>'
from E:/Automation/experiment/ruby_test/string_test.rb:110:in `open'
from E:/Automation/experiment/ruby_test/string_test.rb:110:in `<top (required)>'
from -e:1:in `load'
from -e:1:in `<main>'

Answer 1

由于字符串中的字符无效，您收到invalid byte sequence。您可以先替换字符串中的无效字符：

 content = str.encode( 'UTF-8', invalid: :replace )

然后按换行分开：

 content = content.split( "\n" )

按索引删除数组中的违规元素：

 content.delete_at( 2 )

然后最终将数组重新加入换行符分隔的字符串：

 new_str = content.join( "\n" )
 # => "\nDefault\nWebInit=1"

如何将字符串与`\ xXXXX`和`\ uXXXX`匹配

1 个答案: