无论如何要检索按FQL中的喜欢数量排序的照片吗?
答案 0 :(得分:2)
请注意:我之前从未使用过FQL,但我需要这个昨天的确切解决方案,所以我试了一下!
尝试在上一个答案的第一行添加对“like_info”的引用(也许like_info是新的,因为你问过这个?):
$fql = "SELECT like_info, object_id,src_small,link FROM photo WHERE aid = '2389563453799923709' ORDER BY like_info created DESC";
$param = array(
'method' => 'fql.query',
'query' => $fql,
'callback' => ''
);
$photos = $facebook->api($param);
这可能会给你答案,从大多数到最不喜欢的顺序返回。至少,它对我有用! :)
答案 1 :(得分:1)
请注意:不再需要此解决方案,因为like_info
已添加到照片
所以,我猜这不可能做得很好吗?这是丑陋的解决方案:
$fql = "SELECT object_id,src_small,link FROM photo WHERE aid = '2389563453799923709' ORDER BY created DESC";
$param = array(
'method' => 'fql.query',
'query' => $fql,
'callback' => ''
);
$photos = $facebook->api($param);
if (count($photos) > 0) {
for ($i = 0; $i < count($photos); $i++) {
$objectId = $photos[$i]['object_id'];
$like_count = $facebook->api('/'.$objectId.'/likes');
$photos[$i]['likes'] = count($like_count['data']);
}
}
function cmp($a, $b) {
if ($a['likes'] == $b['likes'])
return 0;
return $a['likes'] > $b['likes'] ? -1 : 1;
}
usort($photos, 'cmp');