一次显示一个数据php

Question

我想知道我是否会按照评分在每个网站名单上显示一个数据？因为我现在拥有的是，在每个站点中按评级显示所有数据顺序。更清楚我真正想要的是：

如果网站等于该人的网站列，则

site: nameone
 - name
 - rating: 10
 - site name: nameone

site: nametwo
 - name
 - rating: 10
 - site name: nametwo

site: nameone
 - name
 - rating: 9
 - site name: nameone

*and so on*

-----------------------------------------------------

到目前为止我的代码：

$rowssite = $db->getSiteOrder();
foreach($rowssite as $siterow)
{
    $rows = $db->people($siterow['acronym']);
    foreach($rows as $row)
    {
        echo $row['name'] . "<br>";
        echo $row['site'] . "<br>";
        echo $row['rate'] . "<br>";
    }

}

我的职能

function getSiteOrder()
    {
        $query = mysqli_query($this->connect,"SELECT * FROM `dynamic_sites` ORDER BY `site_order` ASC") or die(mysql_error());
        while($row = mysqli_fetch_assoc($query))
        {
            $rows[] = $row;
        }
        return $rows;
    }

    function people($siteacronym)
    {
        $query = mysqli_query($this->connect,"SELECT `person`.`mname` as `fullname`, `person`.`msite` as `site`, `person`.`mtoursrate` as `rating` FROM `person` LEFT JOIN `dynamic_sites` ON `person`.`msite`=`dynamic_sites`.`acronym` WHERE `person`.`msite`='".$siteacronym."' ORDER BY `person`.`mtoursrate` DESC") or die(mysql_error());
        while($row = mysqli_fetch_assoc($query))
        {
            $rows[] = $row;
        }
        return $rows;
    }

先谢谢你们！