Question

The XML file that I am having trouble with:


<root>
<datbitmap>
  <paract>
    <action actiontype="startext" eventtype="mouseldouble" program="GISStarter" parameter="LAT=11&amp;Lon=11"/>
  </paract>
  <parbmp bitmap="bmp0044.bmp"/>
  <parbox type="none" halign="center" valign="center"/>
  <parcol fore="-3" back="1" fill="-3"/>
  <pardec min="0" max="31" accrule="0"/>
  <parlay layer="0"/>
  <paropt selectable="1" showstatesyms="1" showstatecols="1" passformula="0" keepformula="0" showoplayer="0"/>
  <parrct hpos="0" vpos="0" width="56" height="62"/>
  <partbl>
  </partbl>
  <partrf hpos="44" vpos="1134" hscale="1" vscale="1" angle="0"/>
</datbitmap>
<dattext>
  <paract>
    <action actiontype="default" eventtype="mouseldouble" dpadr=""/>
  </paract>
  <parbox type="none" halign="left" valign="top"/>
  <parcol fore="0" back="-3" fill="-3"/>
  <pardec min="0" max="31" accrule="0"/>
  <parfnt family="helvetica" bold="0" italic="0" underline="0" size="type:3;p:16"/>
  <parlay layer="0"/>
  <paropt selectable="1" showstatesyms="1" showstatecols="1" showstateprefix="1" showstatesuffix="1" passformula="0" keepformula="0" formularesulttxt="0" windowtitletxt="0" showoplayer="0"/>
  <parrct hpos="0" vpos="0" width="0" height="0"/>
  <partbl>
  </partbl>
  <partrf hpos="109" vpos="1155" hscale="1" vscale="1" angle="0"/>
  <partxt text="GIS"/>
</dattext>

我正在尝试修改第一个操作标记中的属性参数。代码：

Document xmlData = getDocument("data.xml");
  NodeList actionList = xmlDoc.getElementsByTagName("action");
  String attribute = new String("LAT=" + latitudine + "&amp;Lon=" + longitudine);


  for(int j = 0; j < actionList.getLength(); j++) {
    Element actionElement = (Element) actionList.item(j);

    if(actionElement.hasAttribute("parameter")) {
      actionElement.setAttribute("parameter", attribute);
      break;
    } 
  }

正在发生的事情： 1）列表只有一个元素（dattext中的action标记） 2）if（actionElement.hasAttribute（“parameter”））返回true。

运行代码后，xml文件保持不变。

如何修改我想要的属性？

Answer 1

如果你想获得String并保存，或者其他：

TransformerFactory transFactory = TransformerFactory.newInstance();

Transformer transformer = transFactory.newTransformer();

StringWriter buffer = new StringWriter();

transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");

transformer.transform(new DOMSource(document),
  new StreamResult(buffer));

String out= buffer.toString();

如果您想直接发送文件

Transformer trans = TransformerFactory.newInstance().newTransformer();
Result out = new StreamResult(new File("result.xml"));
Source in = new DOMSource(doc);
trans.transform(in, out);

如你所见，有一些选择......

为什么这个Java代码不能修改我的XML文件？

1 个答案: