Question

这是我的SQL

 SELECT DISTINCT(scl_reviews.locid),avg(scl_reviews.rating)
 AS average,scl_locations.name,scl_locations.phone,scl_locations.address,
 scl_location.city,scl_locations.state,scl_locations.zip 
 FROM scl_reviews 
 LEFT JOIN scl_locations ON scl_locations.locid = scl_reviews.locid 
 GROUP BY scl_reviews.locid ORDER BY average DESC LIMIT 100

这意味着它将使用locations获取highest rating并按平均值排序。

问题在于，平均为5的记录似乎以不同的方式查询其位置。 有时我的ID为3115的记录是位置1，有时是位置3。

不太清楚最新情况。我认为这与我的查询有关。

Answer 1

当值相等时，

ORDER BY average DESC无法确定订单的顺序。因此，只需在排序顺序中列出唯一列。您可能希望列号快捷：

ORDER BY 2 DESC, 1 DESC

Answer 2

添加二级订单。当您的第一个订单具有相同的价值时，这就开始了。检查新订单条款：

SELECT DISTINCT(scl_reviews.locid),avg(scl_reviews.rating)
 AS average,scl_locations.name,scl_locations.phone,scl_locations.address,
 scl_location.city,scl_locations.state,scl_locations.zip 
 FROM scl_reviews 
 LEFT JOIN scl_locations ON scl_locations.locid = scl_reviews.locid 
 GROUP BY scl_reviews.locid 
 ORDER BY average DESC, scl_reviews.locid DESC LIMIT 100

sql avg用法导致非法排序结果集

2 个答案: