我如何调用我的两个函数介绍我的主要功能？

Question

所以第一个函数将输入乘以pi并使其成为cos，而第二个函数将相同的输入乘以pi并使其成为sin。然后在int main中，我创建了一个for循环，以便存储来自用户的值，然后我将调用我的两个函数来完成剩下的工作，但它给了我错误，我不知道为什么
这是代码：

#include <iostream>
#include<iomanip>
#include <cmath>
using namespace std; 
double xpicos(double x)
{//const double pi = 3.14159265;

double xpicos = cos(x*pi);
 return xpicos; 
 }  

   double xpisin(double x)
   {const double pi = 3.14159265;
   double xpisin = sin(x*pi);

       return xpisin; 
   }

int mian ()
{
   const double pi = 3.14159265;
double x=0;
double y = 0;
    const int capacity = 200;
    double corners[capacity];
    cout << "enter" ;
    for (int i = 0; i < 200; i++)
    {cin >> corners[i];
    double x = xpicos(corners[i]); 
    double y =xpisin(corners[i]);

    }
  cout << x << "," << y ;

    return 0;
}

Answer 1

好的我包括这个答案来帮助你（尽管我怀疑这个问题会被关闭）。你的代码有一些明显的错误（你拼错了......）。这应该是：

#include <iostream>
#include<iomanip>
#include <cmath>
using namespace std; 
double xpicos(double x)
{
  const double pi = 3.14159265;
  return cos(x*pi);
}  

double xpisin(double x)
{
  const double pi = 3.14159265;
  return sin(x*pi); 
}

int main ()
{
  double x = 0.0;
  double y = 0.0;
  const int capacity = 200;
  double corners[capacity];

  cout << "enter: " << endl;
  for (int i = 0; i < 200; i++){
    cin >> corners[i];
    x = xpicos(corners[i]); 
    y = xpisin(corners[i]);
  }
  cout << x << "," << y << endl;  //you can move this inside the for loop
                                  //if that is what you want

  return 0;
}

Answer 2

您的代码中存在很多错误和错误。您不需要iomanip，main拼写mian，pi不在正确的范围内，您重新声明x和y以及cout for已经失去了'\n'循环，可能需要在每一行之后#include <iostream> #include <cmath> using namespace std; const double pi = 3.14159265; double xpicos(double x) { double xpicos = cos(x*pi); return xpicos; } double xpisin(double x) { double xpisin = sin(x*pi); return xpisin; } int main () { const int capacity = 200; double corners[capacity]; cout << "Enter: " << endl; for (int i = 0; i < 200; i++) { cin >> corners[i]; double x = xpicos(corners[i]); double y = xpisin(corners[i]); cout << x << ", " << y << endl; } return 0; } 。所以更像是：

config.before do
  DatabaseCleaner.start
end

config.after do
  DatabaseCleaner.clean
end

Answer 3

这是它的图片。它给出了奇怪的错误