Question

Java 1.8，Jackson library 2.1.5

我需要覆盖json中对象序列化的行为。

我需要的是忽略序列化json响应中的bonus属性，以防值为null且雇员是Partner员工。但是，尝试下面的代码似乎没有按预期工作。

class Employee{
    private String bonus;
    public String getBonus(){return bonus;}
    public String setBonus(){this.bonus = bonus;}
}

class Partner extends Employee{
    @Override
    @JsonInclude(NON_NULL)
    public String getBonus(){return super.getBonus();}
}

任何帮助？

Answer 1

如果您可以排除所有null属性，那么您可以在课程中使用@JsonSerialize。以下测试使用Jackson 2.1.5成功运行：

import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import org.junit.Test;

public class SomeTest {
    public static class Employee {
        private String bonus;

        public String getBonus() {
            return bonus;
        }

        public void setBonus(String bonus) {
            this.bonus = bonus;
        }
    }

    @JsonSerialize(include = JsonSerialize.Inclusion.NON_NULL)
    public static class Partner extends Employee {
        @Override
        public String getBonus() {
            return super.getBonus();
        }
    }

    @Test
    public void testSerialize() throws Exception {
        Employee employee = new Employee();
        Partner partner = new Partner();

        ObjectMapper objectMapper = new ObjectMapper();
        System.out.println("Employee: " + objectMapper.writeValueAsString(employee));
        System.out.println(" Partner: " + objectMapper.writeValueAsString(partner));
    }
}

<强>输出：

Employee: {"bonus":null}
 Partner: {}

使用JsonInclude批注忽略扩展类

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