我需要使用sed命令删除包含'foobar'的函数, 也许使用另一个默认命令。我会将它应用于很多文件。
main {
engine "map" {
func {
var0 = foo
border = { 1, 1, 1, 1 }
var1 = bar
}
}
engine "map" {
func {
var0 = foo
border = { 1, 2, 1, 2 }
var1 = foobar
}
}
engine "map" {
func {
var0 = foo
border = { 3, 3, 1, 1 }
var1 = bar
}
}
}
提前谢谢你......
答案 0 :(得分:0)
您可以RS
使用null awk -v RS= -v ORS='\n\n' '!/foobar/' file
main {
engine "map" {
func {
var0 = foo
border = { 1, 1, 1, 1 }
var1 = bar
}
}
engine "map" {
func {
var0 = foo
border = { 3, 3, 1, 1 }
var1 = bar
}
}
}
:
<configuration>
<appender name="FILE_DEBUG" class="ch.qos.logback.core.rolling.RollingFileAppender">
<file>${application.home}/logs/debug_log.log</file>
<encoder>
<pattern>%date - [%level] - from %logger in %thread %n%message%n%xException%n</pattern>
</encoder>
<filter class="ch.qos.logback.classic.filter.ThresholdFilter">
<level>DEBUG</level>
</filter>
<rollingPolicy class="ch.qos.logback.core.rolling.TimeBasedRollingPolicy">
<fileNamePattern>${application.home}/logs/debug_log.%d{yyyy-MM-dd}.log</fileNamePattern>
<maxHistory>30</maxHistory>
</rollingPolicy>
</appender>
<appender name="FILE_WARN" class="ch.qos.logback.core.rolling.RollingFileAppender">
<file>${application.home}/logs/warn_log.log</file>
<encoder>
<pattern>%date - [%level] - from %logger in %thread %n%message%n%xException%n</pattern>
</encoder>
<filter class="ch.qos.logback.classic.filter.ThresholdFilter">
<level>WARN</level>
</filter>
<rollingPolicy class="ch.qos.logback.core.rolling.TimeBasedRollingPolicy">
<fileNamePattern>${application.home}/logs/warn_log.%d{yyyy-MM-dd}.log</fileNamePattern>
<maxHistory>60</maxHistory>
</rollingPolicy>
</appender>
<logger name="play" level="INFO"/>
<logger name="application" level="INFO" />
<root level="WARN">
<appender-ref ref="FILE_DEBUG"/>
<appender-ref ref="FILE_WARN"/>
</root>
</configuration>
答案 1 :(得分:0)
您可以类似地使用Perl:
perl -ne 'BEGIN{$/=""} print unless /foobar/' file
$/
是perl的记录分隔符。将其设置为""
可启用段落模式。