我有这样一张桌子
id SERIAL,
user_id INT,
community_id INT[],
表格填写方式:
id | user_id | community_id
1 | 1 | {2, 4}
2 | 5 | {2, 5}
3 | 10 | {2, 4}
我想获得每个社区拥有的COUNT个用户,community_id是数组cuz用户可以同时在多个社区中。
查询应该简单如下:
SELECT community_id, COUNT(user_id) FROM tbl GROUP BY community_id
结果应该是这样的:
community_id | user_count
2 | 3
4 | 2
5 | 1
我不知道如何GROUP BY
数组列。有谁能够帮我 ?
答案 0 :(得分:17)
您可以使用unnest()
获取数据的标准化视图和聚合:
select community_id, count(*)
from (
select unnest(community_id) as community_id
from tbl
) t
group by community_id
order by community_id;
但你应该真正修复你的数据模型。
答案 1 :(得分:1)
select unnest(community_id) community_id
,count(user_id) user_count
from table_name
group by 1 --community_id = 1 and user_count = 2 (index of a column in select query)
order by 1 --
unnest(anyarray):将数组扩展为一组行
即select unnest(ARRAY[1,2])
会给出
unnest
------
1
2