Question

以下是代码：

class Db{
    protected static $connection;
    public function connect(){
        if (!isset(self::$connection)) {
            $config = parse_ini_file('../config.ini');
            self::$connection = new mysqli('localhost',$config['username'],$config['password'],$config['dbname']);
        }
        if (self::$connection === false) {
            die("Error in database connection. Please contact network administrator.");
            return false;
        }
        return self::$connection;
    }
    public function quote($value){
        $connection = $this -> connect();
        return "'".$connection -> real_escape_string(string $value)."'";
    }
}

我在引用函数中收到以下错误： 解析错误：语法错误，意外＆＃39; $ value＆＃39;第48行的D：\ xampp \ htdocs \ fizzy \ submit.php中的（T_VARIABLE）

Answer 1

可能没有$ value的价值。所以你可以这样做：

public function quote($value = ""){

OR

public function quote($value){
        if(isset($value) && $value != "") {
           $connection = $this -> connect();
           return "'".$connection -> real_escape_string(string ($value))."'";
       } else {
           return false;
       }
    }

Answer 2

将string $value更改为(string) $value

Answer 3

删除string

public function quote($value){
    $connection = $this -> connect();
    return "'".$connection -> real_escape_string($value)."'";
                                                 ^
}

Answer 4

查看最后一行代码

return "'".$connection -> real_escape_string(string $value)."'";

此处传递给函数的参数为(string $value)。当您输入$value时，它应为((string)$value)。

解析错误：语法错误T_VARIABLE

4 个答案: