Question

我们有一个表名userProfile，它有一个指针userId to User 表。我们在userProfile上应用内部查询

               PFQuery *query = [PFQuery queryWithClassName:@"UserProfile"];
                [query whereKey:@"userId" equalTo:[PFUser currentUser]];
                [query whereKey:@"relation" equalTo:@"Agent"];
                [query includeKey:@"userId"];
                [query includeKey:@"profileId.userId"];
                query.skip = arrProfiles.count;
                query.limit = 15;
                NSString *searchText = [NSString stringWithFormat:@"%@",self.searchBar.text];


                **PFQuery *innerQuery =[PFUser query];
                [innerQuery whereKey:@"username" matchesRegex:[NSString stringWithFormat:@"(?i)%@",searchText]];
                [query whereKey:@"userId" matchesQuery:innerQuery];**



                [query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {

                }];

但在应用内部查询后我们无法获得任何结果。

Answer 1

在查询中，您说userId必须等于当前用户。但是在内部查询中，您说userId必须将用户与在搜索字段中输入的用户名进行匹配。

这意味着查询必须满足BOTH约束才能返回结果。只有当前用户真正搜索自己时才会发生这种情况。

如果您正在寻找当前用户的个人资料和搜索到的个人资料，您需要使用或如下查询：

PFQuery *firstQuery = [PFQuery queryWithClassName:@"UserProfile"];
[query whereKey:@"userId" equalTo:[PFUser currentUser]];

NSString *searchText = [NSString stringWithFormat:@"%@",self.searchBar.text];

PFQuery *innerQuery =[PFUser query];
[innerQuery whereKey:@"username" matchesRegex:[NSString stringWithFormat:@"(?i)%@",searchText]];

PFQuery *secondQuery = [PFQuery queryWithClassName:@"UserProfile"];
[secondQuery whereKey:@"userId" matchesQuery:innerQuery];

PFQuery *query = [PFQuery orQueryWithSubqueries:[firstQuery, secondQuery]];

[query whereKey:@"relation" equalTo:@"Agent"];
[query includeKey:@"profileId.userId"];
query.skip = arrProfiles.count;
query.limit = 15;

[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {

}];

无法在Parse中对PFUser类应用内部查询

1 个答案: