我有表customer_survey
User_id | Question 1 | Question 2 | Question 3
1 GOOD BAD WORST
2 GOOD GOOD GOOD
3 WORST GOOD WORST
4 BAD BAD BAD
5 BAD GOOD GOOD
6 GOOD BAD GOOD
7 GOOD BEST GOOD
8 GOOD WORST GOOD
我有表score
Id description
1 WORST
2 BAD
3 GOOD
4 BEST
结果:
WORST BAD GOOD BEST
Question 1 1 2 5 0
Question 2 1 3 3 1
Question 3 1 1 5 0
我为此感到困惑。
答案 0 :(得分:0)
简单但麻烦的方法:
SELECT
'Question 1' AS QUESTION,
COUNT(CASE customer_survey.question1 WHEN 'WORST' THEN 1 ELSE NULL END) AS WORST
FROM
customer_survey
UNION ALL
(SELECT
'Question 2' AS QUESTION,
COUNT(CASE customer_survey.question2 WHEN 'GOOD' THEN 1 ELSE NULL END) AS GOOD
FROM
customer_survey)
UNION ALL
(SELECT
'Question 3' AS QUESTION,
COUNT(CASE customer_survey.question3 WHEN 'BAD' THEN 1 ELSE NULL END) AS BAD
FROM
customer_survey)
UNION ALL
(SELECT
'Question 4' AS QUESTION,
COUNT(CASE customer_survey.question4 WHEN 'BEST' THEN 1 ELSE NULL END) AS BEST
FROM
customer_survey)