我应该如何在java对象中表示数据库元组？

Question

我应该编写一些代码来从oracle数据库读取和写入数据。 IO是用sql处理的，但问题出在java类中，它存储来自每个元组的数据。

到目前为止，我已经编写了一个父抽象类来表示任何表中的任何元组。然后我就为每一张桌子写了每一堂课。这很乏味，我相信有更聪明的方法可以做到这一点。每个类基本相同，但具有不同名称的不同属性，更改它们时很容易出错。

父类是这样的：

public abstract class DBEntity {

  String entName;
  String key;
  String insertFormat;
  String values;
  boolean isSet;

  public boolean addTo(OracleHelper db) {
    return db.sentence(insertValues());
  }

  public abstract String insertValues();

  public boolean add(OracleHelper db) {
    return db.sentence(insertValues());
  }

  public String find(OracleHelper db, String key) {
    return db.query("select * from " + entName + "where " + this.key + " = " + key);
  }

  public String[] find(OracleHelper db, String value, String attribute) {
    return db.query("select * from " + entName + "where " + attribute + " = " + value).split("\n");
  }

  public abstract DBEntity[] getEntities(OracleHelper db, String value, String attribute) throws IncorrectConstructionValues;
}

儿童班是这样的：

public class Genre extends DBEntity {

  String name;
  String description;

  static String entName = "genre";
  static String insertFormat = "insert into genre(name, description) values('%s', '%s')";
  int PARAM_NUM = 4;

  public Genre(String name, String description) {
    this.name = name;
    this.description = description;
    isSet = true;
  }

  public Genre() {
    isSet = false;
  }

  /**
   * Creates a Game with the first result of the value-attribute combination.
   * If you're sure there is only one possible match use this. Else use another
   * combination.
   *
   * @param db
   * @param attribute
   * @param value
   * @throws IncorrectConstructionValues
   */
  public Genre(OracleHelper db, String attribute, String value) throws IncorrectConstructionValues {

    try {
      String[] params = find(db, attribute, value)[0].split("||");
      name = params[0];
      description = params[1];
    } catch (Exception e) {
      throw new IncorrectConstructionValues("No hay ningún elemento con esos valores");
    }
    isSet = true;
  }

  public Genre(String allValues) throws IncorrectConstructionValues {


    try {
      String[] params = allValues.split("||");
      name = params[0];
      description = params[1];
    } catch (Exception e) {
      throw new IncorrectConstructionValues("Algún valor no corresponde" +
          "con el de un atributo para esta clase");
    }
    isSet = true;
  }

  @Override
  public String insertValues() {
    if (isSet) {
      return String.format(insertFormat, name, description);
    } else {
      return null;
    }
  }

  @Override
  public DBEntity[] getEntities(OracleHelper db, String value, String attribute) throws IncorrectConstructionValues {
    String[] tuples = find(db, value, attribute);
    Genre[] games = new Genre[tuples.length];
    for (int i = 0; i < games.length; i++) {
      games[i] = new Genre(tuples[i]);
    }
    return games;
  }
}

有没有更好的简单方法呢？