如何限制R中函数的长度

Question

我希望这段代码能够工作，但是（t）的长度和w（t）的长度不同，所以它阻止了我的所有代码。我能知道两者的长度是多少吗？

    S(t)= S(0)exp(0.06t+0.20w(t))  #(1)
    with S(0) =20
    w(t) = standard Brownian movement

    t <- seq(1,900,length=900) #the path or step=1 for 3 years (1y=300)
    length(t)
    v = matrix(rnorm(log(20)+0.06*t,sd=sqrt((0.20)^(2)*t)),nrow=5)
    z = matrix(NA, ncol=900, nrow=5)
    w = function(t)
    {c(0,cumsum(v))}
    length(w(t))
    Bn <-log(20)+ 0.06*t +0.20*w(t)
    Br <- log(Bn)
    plot(t,Br,type="l",xlab="Temps") 

    for (i in 1:5) # I need to draw 5 path of the function(1)
    {z[i,] = c(0,cumsum(Br[i,]))}
    dim(z)
    u= apply(z,2,mean) #mean of the 5 path

    plot(t,z[1,],xlab="temps",type="l",ylab="Brownian Movement")
    for (i in 1:5){lines(t,z[i,])}
    lines(t,u,lwd=2,col="red")

感谢您的时间

Answer 1

使用w= function(t){c(cumsum(v))}使所有变量都有900个元素。 Br只有一个维度，因此您必须使用Br[i]。这有效：

t <- seq(1,900,length=900) #the path or step=1 for 3 years (1y=300)
length(t)
v = matrix(rnorm(log(20)+0.06*t,sd=sqrt((0.20)^(2)*t)),nrow=5)
z = matrix(NA, ncol=900, nrow=5)
w = function(t)
{c(cumsum(v))}
length(w(t))
Bn <-log(20)+ 0.06*t +0.20*w(t)
Br <- log(Bn)
length(Bn)
 length(Br)
plot(t,Br,type="l",xlab="Temps")

for (i in 1:5) # I need to draw 5 path of the function(1)
{z[i,] = c(cumsum(Br[i]))}
dim(z)
u= apply(z,2,mean) #mean of the 5 path

plot(t,z[1,],xlab="temps",type="l",ylab="Brownian Movement")
for (i in 1:5){lines(t,z[i,])}
lines(t,u,lwd=2,col="red")