Question

我正在尝试取得

的结果

SELECT SUM(pont) AS totalpont
      FROM
    (SELECT jogador.pont from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j1 
    UNION 
    SELECT jogador.pont from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j2
    UNION
    SELECT jogador.pont from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j3 
    UNION
    SELECT jogador.pont from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j4) T

和

SELECT mercado FROM variaveis

进入相同的查询，两个独立的数据集并排，例如，查询1返回1,2,3,4,5，查询2返回A，B，C。我希望结果为1，A，2，B，3，C，4，null，5，null

Answer 1

我希望您需要合并这些查询并需要一个SUM，因为您可以使用＆＃39; AS＆＃39;语法（将mercado重命名为pont），这样你就可以求和。

SELECT SUM(COALESCE(pont, 0)) as totalpont, SUM(COALESCE(mercado, 0)) AS totalmercado
      FROM
    (SELECT jogador.pont, NULL AS mercado from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j1 
    UNION 
    SELECT jogador.pont, NULL AS mercado from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j2
    UNION
    SELECT jogador.pont, NULL AS mercado from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j3 
    UNION
    SELECT jogador.pont, NULL AS mercado from jogador,usuarios WHERE email='like' and jogador.id=usuarios.j4) T
    UNION
    SELECT NULL AS pont, mercado  FROM variaveis )T

MySQL加入2个查询

1 个答案: