我需要一些帮助,使用Alamofire通过Twilio的API使用用户名/密码对网页进行POST。
我之前使用过GitHub的SwiftRequest,但这不支持Swift 2.0。
我使用的代码(使用SwiftRequest)是:
var data = [
"To" : mobileInput.text as String!,
"From" : twilioSMSFrom,
"Body" : String(code) as String
]
var swiftRequest = SwiftRequest()
swiftRequest.post("https://api.twilio.com/2010-04-01/Accounts/\(twilioUsername)/Messages",
auth: ["username" : twilioUsername, "password" : twilioPassword],
data: data,
callback: {err, response, body in
if err == nil {
println("Success: \(response)")
} else {
println("Error: \(err)")
}
})
如何将其翻译为使用Alamofire?
我尝试过搜索解决方案,但可以找到。
有人能帮助我吗?
答案 0 :(得分:1)
尝试这样的事情:
Alamofire.request(.POST, "https://api.twilio.com/2010-04-01/Accounts/\(twilioUsername)/Messages", parameters: ["username": twilioUsername, "password" : twilioPassword])
.responseJSON { response in
print(response.request)
print(response.response)
print(response.result)
if let JSON = response.result.value {
print("Did receive JSON data: \(JSON)")
}
else {
print("JSON data is nil.")
}
}
你一定要查看他们的github页面 - https://github.com/Alamofire/Alamofire
答案 1 :(得分:1)
我明白了。
使用Alamofire的解决方案:
let data = [
"To" : mobileInput.text as String!,
"From" : twilioSMSFrom,
"Body" : String(code) as String
]
Alamofire.request(.POST, "https://\(twilioUsername):\(twilioPassword)@api.twilio.com/2010-04-01/Accounts/\(twilioUsername)/Messages", parameters: data)
.responseJSON { response in
print(response.request)
print(response.response)
print(response.result)
}
答案 2 :(得分:0)
这是SWIFT 2.2 VERSION的最新答案 尝试这个可以帮助你......
参数: -
let params : Dictionary = ["YourKEY" : "YourVALUE"]
发布Request_Form: -
Alamofire.request(.POST,"Post Your Url HERE", parameters: params, encoding:.JSON).responseJSON
{
response in switch response.result
{
case .Success(let JSON):
// print("Success with JSON: \(JSON)")
//converting json into NSDictionary
let response = JSON as! NSDictionary
print(response)
var array = NSMutableArray!()
//converting respose form into NSMutableArray formate
array = response.valueForKey("countryList")as? NSMutableArray
//example if there is an id
// let userId = response.objectForKey("id")!
case .Failure(let error):
print("Request failed with error: \(error)")
}
}