Question

我的CSV文件如下所示：

Mike,6
Mike,5
Bill,3
Bill,1
Sally,4
Sally,2

我想修改它，所以计数按名称求和，看起来像这样：

Mike,11
Bill,4
Sally,6

Answer 1

看看熊猫图书馆。

df = pd.read_csv('data.csv')
df_grouped = df.groupby('name').sum()

这里有更多细节

http://pandas.pydata.org/pandas-docs/stable/groupby.html

Answer 2

def records_from_file(fname, column_names):
    with open(fname,'r') as input_handler:
    for line in input_handler:
        line = line.strip('\n') #strip out newline
        x={} #this creates x as an empty dictionary
        for i in range(len(column_names)):
            x[column_names[i]] = line.split(",")[i]  #append each key and value to the dictionary
        yield x

record_stream = records_from_file('names.csv',['name', 'count'])

class Object:                   #Object to store unique data
    def __init__(self, name, count):
        self.name = name
        self.count = count

rownum = 0 #Row Number currently iterating over
list = []  #List to store objects

def checkList(name, count):
    for object in list:  #Iterate through list        
        count=int(count)
        if object.name == name:  #Check if name and produce combination exists
            object.count += int(count) #If it does add to amount variable and break out
            return
    newObject = Object(name, count) #Create a new object with new name, produce, and amount
    list.append(newObject)  #Add to list and break out

for record in record_stream:  #Iterate through all the rows
    name = record['name']  #Store name
    count = int(record['count']) #Store count
    checkList(name, count)

rownum += 1

for each in list: #Print out result
    print each.name,each.count

Answer 3

import pandas as pd

df = pd.read_csv('names.csv')
df.columns = ['name','count']
df_grouped = df.groupby('name').sum()
print df_grouped

使用Python聚合CSV记录

3 个答案: