我希望能够获得枚举(默认)的int值以及文本值(例如2或“TestTwo”)。我试过下面的代码:
在父母:
@XmlElement(name="ProjectType")
private ProjectType projectType;
在Enum中:
@XmlRootElement(name = "Proj")
@XmlType
@XmlEnum(Integer.class) //Which class to set here??
public enum ProjectType implements java.io.Serializable {
@XmlEnumValue("2") TestTwo(2),
@XmlEnumValue("3") TestThree(3);
private int projectType = 0;
private ProjectType(int projectType) {
this.projectType = projectType;
}
}
但是当我运行mule项目时会遇到异常:
Caused by: java.lang.ExceptionInInitializerError
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) ~ [?:1.8.0_51]
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) ~[?:1.8.0_51]
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[?:1.8.0_51]
at java.lang.reflect.Method.invoke(Method.java:497) ~[?:1.8.0_51]
at java.lang.Class.getEnumConstantsShared(Class.java:3320) ~[?:1.8.0_51]
at java.lang.System$2.getEnumConstantsShared(System.java:1249) ~[?:1.8.0_51]
at java.util.EnumMap.getKeyUniverse(EnumMap.java:752) ~[?:1.8.0_51]
at java.util.EnumMap.<init>(EnumMap.java:138) ~[?:1.8.0_51]
和
Caused by: java.lang.NullPointerException
at com.test.demo.ProjectType.values(ProjectType.java:1) ~[?:?]
at com.test.demo.ProjectType.<init>(ProjectType.java:22) ~[?:?]
at com.test.demo.ProjectType.<clinit>(ProjectType.java:13) ~[?:?]
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) ~[?:1.8.0_51]
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) ~[?:1.8.0_51]
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[?:1.8.0_51]
at java.lang.reflect.Method.invoke(Method.java:497) ~[?:1.8.0_51]
at java.lang.Class.getEnumConstantsShared(Class.java:3320) ~[?:1.8.0_51]
at java.lang.System$2.getEnumConstantsShared(System.java:1249) ~[?:1.8.0_51]
at java.util.EnumMap.getKeyUniverse(EnumMap.java:752) ~[?:1.8.0_51]
at java.util.EnumMap.<init>(EnumMap.java:138) ~[?:1.8.0_51]
我看不出这里有什么问题?
答案 0 :(得分:1)
使用像这样的父类
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Elem {
@XmlElement(name="ProjectType")
private ProjectType projectType;
//...
}
和你发布的枚举,编组没问题:
<elem>
<ProjectType>2</ProjectType>
</elem>
如果我将枚举更改为
@XmlRootElement(name = "Proj")
@XmlType
@XmlEnum(String.class)
public enum ProjectType {
@XmlEnumValue("II") // or @XmlEnumValue(2)
TestTwo(2),
@XmlEnumValue("III") // or @XmlEnumValue(3)
TestThree(3);
// ....
}
输出变为
<elem>
<ProjectType>II</ProjectType>
</elem>
我认为JAXB没有特别的问题。 修改添加了主类。
public class Main { private static final String XMLIN = "hello.xml"; void marshal() throws Exception { Elem root = new Elem(); root.setProjectType( ProjectType.TestTwo ); JAXBContext jc = JAXBContext.newInstance( Elem.class ); Marshaller m = jc.createMarshaller(); m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); m.marshal( root, System.out ); } void unmarshal() throws Exception { JAXBContext jc = JAXBContext.newInstance( Elem.class ); Unmarshaller u = jc.createUnmarshaller(); Elem elem = (Elem)u.unmarshal( new File( XMLIN ) ); System.out.println( "elem projectType " + elem.getProjectType() ); } public static void main( String[] args ) throws Exception { Main main = new Main(); main.marshal(); main.unmarshal(); } }