通过＆＃34;变量＆＃34;添加到目前为止的小时数。在PHP不静态

Question

我已将日期和时间存储在数据库中2015-06-31 14:00我希望通过变量向hours字段添加一些date如何添加

<?php
//set an date and time to work with
$start = '2015-06-31 14:00';
$hours='05:00';

//display the converted time
echo date('Y-m-d H:i',strtotime("+{$hours} hours",strtotime($start)));
?>

Answer 1

检查

//set an date and time to work with
$start = '2015-06-30 14:00';
$hours= 5;

//display the converted time
echo date('Y-m-d H:i',strtotime("+{$hours} hours",strtotime($start)));

输出为2015-06-30 19:00

Answer 2

试试这个

<?php
$start = '2015-10-31 14:00';
$hours = '05:00';

$date = new DateTime($start);
$date->modify(sprintf("+%d hours", $hours));
echo $date->format("Y-m-d H:i");
?>

<强>输出：

2015-10-31 19:00