Question

我正在尝试制作一个添加游戏，但我随机生成的数字要添加的并不是随机的，即使我每次都指定它们是随机的。有人帮忙。我还在处理我的项目，但我仍然坚持这一部分。到目前为止我的代码：

package addgame;
import java.util.Random;
import java.util.Scanner;
public  class add {
    private static Scanner console;

    public static void main(String[] args) {
        System.out.println(
                "We are going to play an adding game. Type your answer.");
        equation();

    }

    public static void Answer(Scanner console) {

    }

    public static void equation() {
        int tries = 0;
        while (tries == 0) {
            Random rand = new Random();
            int nums = rand.nextInt(25) + 6;
            int totalnums = rand.nextInt(4) + 1;
            int sumAns = 0;
            for (int i = 1; i <= totalnums + 1; i++) {
                System.out.print(nums + "+ ");
                sumAns += nums;

            }
            System.out.print("= ");

            console = new Scanner(System.in);
            int ans = console.nextInt();
            System.out.println(sumAns);
        }
    }
}

Answer 1

您必须将随机数发放器放在for-loop：

中

    private static Scanner console;

    public static void main(String[] args) {
        System.out.println(
                "We are going to play an adding game. Type your answer.");
        equation();

    }

    public static void Answer(Scanner console) {

    }

    public static void equation() {
        int tries = 0;
        while (tries == 0) {
            Random rand = new Random();
            int nums = 0;
            int totalnums = rand.nextInt(4) + 1;
            int sumAns = 0;
            for (int i = 1; i <= totalnums + 1; i++) {
                nums = rand.nextInt(25) + 6; //Changed
                System.out.print(nums + "+ ");
                sumAns += nums;

            }
            System.out.print("= ");

            console = new Scanner(System.in);
            int ans = console.nextInt();
            System.out.println(sumAns);
        }
    }
}

为什么我的打印方程式打印相同的数字？

1 个答案: