Question

我有json，其中属性名称有一个特殊的char。试图用喷雾json解析它。下面是代码如何在json @xml中获取属性名称：lang被解析为case类。

import spray.json._
import DefaultJsonProtocol._

object SpecialCharInName extends App {

  case class Person(name: String, `@xml:lang`: String)

  val json = """ {"name":"MyName", "@xml:lang":"US"} """

  object PersonProtocol extends DefaultJsonProtocol {
    implicit val personFormat = jsonFormat2(Person)
  }

  import PersonProtocol._
  val person = json.parseJson
  val personClass = person.convertTo[Person]

  println(personClass)

}

上面的代码抛出异常，如下所示

[error] (run-main-0) spray.json.DeserializationException: Object is missing required member '@xml$colonlang'
spray.json.DeserializationException: Object is missing required member '@xml$colonlang'
at spray.json.package$.deserializationError(package.scala:23)
at spray.json.ProductFormats$class.fromField(ProductFormats.scala:60)
at c.c.s.f.v.d.SpecialCharInName$PersonProtocol$.fromField(SpecialCharInName.scala:12)
at spray.json.ProductFormatsInstances$$anon$2.read(ProductFormatsInstances.scala:56)
at spray.json.ProductFormatsInstances$$anon$2.read(ProductFormatsInstances.scala:46)
at spray.json.JsValue.convertTo(JsValue.scala:31)
at c.c.s.f.v.d.SpecialCharInName$.delayedEndpoint$com$comcast$sv$fabric$vimond$domain$SpecialCharInName$1(SpecialCharInName.scala:20)
at c.c.s.f.v.d.SpecialCharInName$delayedInit$body.apply(SpecialCharInName.scala:6)
at scala.Function0$class.apply$mcV$sp(Function0.scala:40)
at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
at scala.App$$anonfun$main$1.apply(App.scala:76)
at scala.App$$anonfun$main$1.apply(App.scala:76)
at scala.collection.immutable.List.foreach(List.scala:381)
at scala.collection.generic.TraversableForwarder$class.foreach(TraversableForwarder.scala:35)
at scala.App$class.main(App.scala:76)
at c.c.s.f.v.d.SpecialCharInName$.main(SpecialCharInName.scala:6)
at c.c.s.f.v.d.SpecialCharInName.main(SpecialCharInName.scala)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)
Caused by: java.util.NoSuchElementException: key not found: @xml$colonlang
at scala.collection.MapLike$class.default(MapLike.scala:228)
at scala.collection.AbstractMap.default(Map.scala:59)
at scala.collection.MapLike$class.apply(MapLike.scala:141)
at scala.collection.AbstractMap.apply(Map.scala:59)
at spray.json.ProductFormats$class.fromField(ProductFormats.scala:57)
at c.c.s.f.v.d.SpecialCharInName$PersonProtocol$.fromField(SpecialCharInName.scala:12)
at spray.json.ProductFormatsInstances$$anon$2.read(ProductFormatsInstances.scala:56)
at spray.json.ProductFormatsInstances$$anon$2.read(ProductFormatsInstances.scala:46)
at spray.json.JsValue.convertTo(JsValue.scala:31)
at c.c.s.f.v.d.SpecialCharInName$.delayedEndpoint$com$comcast$sv$fabric$vimond$domain$SpecialCharInName$1(SpecialCharInName.scala:20)
at c.c.s.f.v.d.SpecialCharInName$delayedInit$body.apply(SpecialCharInName.scala:6)
at scala.Function0$class.apply$mcV$sp(Function0.scala:40)
at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
at scala.App$$anonfun$main$1.apply(App.scala:76)
at scala.App$$anonfun$main$1.apply(App.scala:76)
at scala.collection.immutable.List.foreach(List.scala:381)
at scala.collection.generic.TraversableForwarder$class.foreach(TraversableForwarder.scala:35)
at scala.App$class.main(App.scala:76)
at c.c.s.f.v.d.SpecialCharInName$.main(SpecialCharInName.scala:6)
at c.c.s.f.v.d.SpecialCharInName.main(SpecialCharInName.scala)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)

提前感谢您的帮助。

Saad的

Answer 1

import spray.json._
import DefaultJsonProtocol._

object SpecialCharInName extends App {

  case class Person(name: String, `@xml:lang`: String)

  val json = """ {"name":"MyName", "@xml:lang":"US"} """

  object PersonProtocol extends DefaultJsonProtocol {
    implicit val personFormat = jsonFormat(Person.apply, "name", "@xml:lang")
  }

  import PersonProtocol._

  val person = json.parseJson
  val personClass = person.convertTo[Person]
  println(personClass)
}

享受：）

简单地说，使用接受构建器方法的专用jsonFormat方法（如apply）和必须在要解析的JSON文档中出现的命名属性列表。在您的情况下，默认值不会很好。

使用特殊字符喷涂json属性

1 个答案: