我有这个JSON字符串
[
{
uri : '/someuri/one',
title : 'Title 1',
displayLocation : 'ACTION_MENU',
masterData : 'LOCATION',
iconClass : 'icon-class-1'
},
{
uri : '/someuri/two',
title : 'Title 2',
displayLocation : 'ACTION_MENU',
masterData : 'LOCATION',
iconClass : 'icon-class-2'
},
{
uri : '/someuri/three',
title : 'Title 3',
displayLocation : 'ACTION_MENU',
masterData : 'JOB',
iconClass : 'icon-class-3'
},
{
uri : '/someuri/four',
title : 'Title 4',
displayLocation : 'SUMMARY',
masterData : 'LOCATION',
iconClass : 'icon-class-4'
}
]
我正在将其转换为
[
{
iconClass : 'icon-class-1',
id : 'anythingUnique',
text : 'Title 1'
},
{
iconClass : 'icon-class-2',
id : 'anythingUnique',
text : 'Title 2'
}
]
使用以下代码
function myCustomFilter(inputJSONStr) {
return _.each(inputJSONStr.filter(function(action){
return action.masterData === 'LOCATION' && action.displayLocation === 'ACTION_MENU';
}), function (action) {
return [{iconClass: action.iconClass, id: 'anythingUnique', text: action.title}];
});
但是它返回了我的JSON字符串
[
{
uri : '/someuri/one',
title : 'Title 1',
displayLocation : 'ACTION_MENU',
masterData : 'LOCATION',
iconClass : 'icon-class-1'
},
{
uri : '/someuri/two',
title : 'Title 2',
displayLocation : 'ACTION_MENU',
masterData : 'LOCATION',
iconClass : 'icon-class-2'
}
]
任何人都可以建议我做错了吗?
答案 0 :(得分:1)
You could use map to do this:
_(inputJSONStr).filter({masterData: 'LOCATION', displayLocation: 'ACTION_MENU'})
.map(function(a) {
return {iconClass: a.iconClass, id: 'anythingUnique', text: a.title};
}).value();
I've changed your filter a little, but you could do it your way if you wanted, and I've used a functional approach with chaining, but you could do it imperatively if that makes you more comfortable. Map effectively replaces an array element with the returned element.