我来自PHP世界,并试图在业余时间学习Java Spring框架。在我决定向表单添加验证之前,我做得很好。以下是我的代码。
package com.invokedynamic.spring;
import java.text.DateFormat;
import java.util.Date;
import java.util.HashMap;
import java.util.Locale;
import java.util.Map;
import javax.validation.Valid;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.validation.BindingResult;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.servlet.ModelAndView;
import com.invokedynamic.spring.User;
/**
* Handles requests for the application home page.
*/
@Controller
public class RestController {
private static final Logger logger = LoggerFactory.getLogger(RestController.class);
private Map<String, User> users = new HashMap<String, User>();
public RestController() {
// pre-initialize the list of issuers available ...
users.put("pinkal", new User("pinkal", "pinkal123", "pinkal@gmail.com", "USA"));
users.put("mahesh", new User("mahesh", "mahesh123", "mahesh@gmail.com", "USA"));
}
/**
* Simply selects the home view to render by returning its name.
*/
@RequestMapping(value = "/", method = RequestMethod.GET)
public String home(Locale locale, Model model) {
logger.info("Welcome home! The client locale is {}.", locale);
Date date = new Date();
DateFormat dateFormat = DateFormat.getDateTimeInstance(DateFormat.LONG, DateFormat.LONG, locale);
String formattedDate = dateFormat.format(date);
model.addAttribute("serverTime", formattedDate );
return "status";
}
@RequestMapping(value="/users", method=RequestMethod.GET)
@ResponseBody
public Map<String, User> getAllUsers() {
logger.info("Inside getAllUsers() method...");
return users;
}
@RequestMapping(value="/user/{username}", method=RequestMethod.GET)
@ResponseBody
public User getUserByUsername(@PathVariable("username") String username) {
User user = users.get(username);
if (user != null) {
logger.info("Inside sgetUserByUsername, returned: " + user.toString());
} else {
logger.info("Inside getUserByUsername, ticker: " + username + ", NOT FOUND!");
}
return user;
}
@RequestMapping(value="/user/delete/{username}", method=RequestMethod.GET)
@ResponseBody
public User deleteIssuerByTicker(@PathVariable("username") String username) {
User user = users.remove(username);
if (user != null) {
logger.info("Inside deleteIssuerByTicker, deleted: " + user.toString());
} else {
logger.info("Inside deleteIssuerByTicker, ticker: " + username + ", NOT FOUND!");
}
return user;
}
@RequestMapping(value="/user/create", method=RequestMethod.GET)
public ModelAndView addUser() {
return new ModelAndView("addUser", "command", new User());
}
@RequestMapping(value="/user/addUser", method=RequestMethod.POST)
@ResponseBody
public String addUser(@Valid @ModelAttribute("user") User user, BindingResult result, Model model) {
if (result.hasErrors()) {
return "addUser";
}
if (user != null) {
logger.info("Inside addIssuer, adding: " + user.toString());
} else {
logger.info("Inside addIssuer...");
}
users.put(user.getUsername(), user);
return "{\"success\":1}";
}
}
验证失败而不是渲染&#34; addUser&#34;查看它只是打印&#34; addUser&#34;在屏幕上。我究竟做错了什么?可以看到完整的来源here。
修改
如果我按照以下几个答案的建议从@ResponseBody
方法移除addUser
,我会
HTTP状态500 - java.lang.IllegalStateException:都不是 BindingResult也不是bean名称&#39;命令的明确目标对象。 可用作请求属性
答案 0 :(得分:1)
这是因为您正在使用@ResponseBody
注释。
当您使用此注释时,从此处返回的数据将被视为存在于正文中的数据,而不是作为视图名称处理,并由viewResolver
解析。
还要将以下属性添加到您的表单标记中,如下所示
<f:form method="POST" action="addUser" commandName="user">
答案 1 :(得分:0)