echo $approver;
输出&#34;主管&#34;在网页上,但代码echo "Supervisor is working <br />"
不会输出任何内容。
$approver = $_POST['approver'];
echo $approver;
echo "<br />";
//echo "It is working <br />";
if ($approver == "Supervisor")
echo "Supervisor is working <br />";
答案 0 :(得分:3)
$_POST["approver"]
字符串中有一些空格很可能。为避免这种情况,请尝试更改:
$approver = $_POST['approver'];
为:
$approver = trim($_POST['approver']);