我检查了以下内容:
How to find out what character key is pressed? http://www.javascriptkit.com/javatutors/javascriptkey2.shtml http://www.w3schools.com/jsref/event_key_keycode.asp http://forums.asp.net/t/1782329.aspx?How+to+detect+which+Key+is+pressed+in+Javascript
它都不起作用。 在我按下一些字符并按回车键后,我当前的代码给了我一个警告“未定义”。
我目前的代码:
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="X-UA-Compatible" content="IE=edge" />
<meta http-equiv='Content-Type' content='text/html;charset=UTF-8'/>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script src="https://sapui5.netweaver.ondemand.com/resources/sap-ui-core.js" id="sap-ui-bootstrap" data-sap-ui-libs="sap.ui.ux3,sap.ui.commons,sap.ui.table, sap.ui.richtexteditor" data-sap-ui-theme="sap_goldreflection" data-sap-ui-language="en">
</script>
<script>
function showKeyPress(evt)
{
alert("onkeypress handler: \n"
+ "keyCode property: " + evt.keyCode + "\n"
+ "which property: " + evt.which + "\n"
+ "charCode property: " + evt.charCode + "\n"
+ "Character Key Pressed: "
+ String.fromCharCode(evt.charCode) + "\n"
);
}
var oInput2 = new sap.ui.richtexteditor.RichTextEditor({
id : 'ta',
tooltip : 'This is a tooltip',
width: '100%',
rows : 4,
wrapping : false,
change: function(e)
{
var code = oInput2.getValue();
//console.log(code);
var regex = /(<([^>]+)>)/ig
// var result = body.replace(regex, "");
code = code.replace(/ |/g, '');
code = code.replace(regex,"");
//console.log(code);
var ex = code.split(' ');
//console.log(ex);
var array = ["<?","<?php","?>"];
var keyWords = ['__halt_compiler', 'abstract', 'and', 'array', 'as', 'break', 'callable', 'case', 'catch', 'class', 'clone', 'const', 'continue', 'declare', 'default', 'die', 'do', 'echo', 'else', 'elseif', 'empty', 'enddeclare', 'endfor', 'endforeach', 'endif', 'endswitch', 'endwhile', 'eval', 'exit', 'extends', 'final', 'for', 'foreach', 'function', 'global', 'goto', 'if', 'implements', 'include', 'include_once', 'instanceof', 'insteadof', 'interface', 'isset', 'list', 'namespace', 'new', 'or', 'print', 'private', 'protected', 'public', 'require', 'require_once', 'return', 'static', 'switch', 'throw', 'trait', 'try', 'unset', 'use', 'var', 'while', 'xor'];
var colored = "";
ex.forEach(function(entry){
//alert(array.indexOf('<p>'+entry+'</p>'));
alert(KeyboardEvent.location);
var num = 0;
if(array.indexOf(entry) > -1)
{
num = 1;
}
if(keyWords.indexOf(entry) > -1)
{
num = 2;
}
switch(num)
{
case 1:
colored += "<span style='color:red'> "+entry+"</span> ";
break;
case 2:
colored += '<span style="color:blue"> '+entry+'</span> ';
break;
default:
colored += entry+ ' ';
}
})
//console.log(colored);
oInput2.setValue(colored);
}
});
// function cleanCode(a)
// {
// a = a.replace(/<span style="color: red;">/g, '');
// return a;
// }
oInput2.placeAt('content');
oInput2.onkeypress = function(event)
{
if(event.keyCode == 32)
{
alert("space");
console.log("space");
}
}
</script>
<script type="text/javascript">
function myKeyPress(e){
var keynum;
if(window.event){ // IE
keynum = e.keyCode;
}else
if(e.which){ // Netscape/Firefox/Opera
keynum = e.which;
}
alert(String.fromCharCode(keynum));
}
</script>
</head>
<body class="sapUiBody" onkeydown="myKeyPress(e);">
<div id="content"></div>
</body>
</html>
我在控制台中也有此消息(警告):
'KeyboardEvent.keyLocation'已弃用。请用 'KeyboardEvent.location'而不是
答案 0 :(得分:1)
嗨,请查看this示例,它包含一个包含多个键的示例。 html中的代码应该足够了:
window.addEventListener("keydown", function(e) {
//your code here
});
答案 1 :(得分:0)
<!DOCTYPE html>
<html>
<body>
<script>
window.addEventListener("keydown", function(e) {
//your code here
});
</script>
</body>
</html>
答案 2 :(得分:0)
正确使用的事件是&#34; keydown&#34;。
通过以下方式使用keyCode
或which
按下键:
(e.keyCode||e.which)
使用此示例:
window.onkeydown=function(e){
alert(((e.keyCode||e.which)==32)?'Spacebar pressed.':'Spacebar was not pressed.');
}