Question

我正在尝试创建一个月的序列从1月到12月3次。即。一月二月损伤。。。。十二月一月二月损伤。。。。十二月一月二月损伤。。。。癸

我试过这段代码

rep(c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sept","Oct","Nov","Dec"),each=3)

但它会生成这样的结果

[1] "Jan"  "Jan"  "Jan"  "Feb"  "Feb"  "Feb"  "Mar"  "Mar"  "Mar"  "Apr"  "Apr"  "Apr" 
[13] "May"  "May"  "May"  "Jun"  "Jun"  "Jun"  "Jul"  "Jul"  "Jul"  "Aug"  "Aug"  "Aug" 
[25] "Sept" "Sept" "Sept" "Oct"  "Oct"  "Oct"  "Nov"  "Nov"  "Nov"  "Dec"  "Dec"  "Dec"

但我想要Jan Feb Mar .... Dec Jan Feb Mar ..... Dec Jan Feb Mar ... Dec

由于 Harshad

Answer 1

我们可以使用month.abb代替c('Jan', 'Feb')等。

 rep(month.abb, 3)

完整月份名称

 rep(month.name, 3)

Answer 2

使用times=3

rep(c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sept","Oct","Nov","Dec"),times=3)
#  [1] "Jan"  "Feb"  "Mar"  "Apr"  "May"  "Jun"  "Jul"  "Aug"  "Sept" "Oct"  "Nov"  "Dec"  "Jan" 
# [14] "Feb"  "Mar"  "Apr"  "May"  "Jun"  "Jul"  "Aug"  "Sept" "Oct"  "Nov"  "Dec"  "Jan"  "Feb" 
# [27] "Mar"  "Apr"  "May"  "Jun"  "Jul"  "Aug"  "Sept" "Oct"  "Nov"  "Dec"

如何创建特定月份和/或日期序列“n”次

2 个答案: