Question

我正在试图弄清楚如何在bash中创建一个while-do-done脚本，这将允许我选择选项1-4，如果我使用1-4将允许我再次选择按'n '退出或任何键继续。感谢您的任何意见，我非常感谢。

#!/bin/bash
#while-do-done
RED='\033[0;31m'
NC='\033[0m'

#options 1-4 have options, option 5-x is else command
echo "Type one of the following:"
echo "1 - whoami"
echo "2 - df"
echo "3 - date"
echo "4 - cal"
echo -n "select option:"

read option

while [ $option == "1" ]
 whoami

echo "Enter another command?"

echo "Press 'n' to exit. Any key to continue"

if [ $option == "n" ]
 then exit
fi

while [ $option == "2" ]
 df

while [ $option == "3" ]
 date

while [ $option == "4" ]
 cal

while [ $option == * ]
 printf "${RED} You made an invalid selection. Exiting.${NC}"

exit 0

Answer 1

我认为这就是你所追求的目标。

#!/usr/bin/env bash

RED='\033[0;31m'
NC='\033[0m'

showmenu() {
  echo "Type one of the following:"
  echo " 1 - whoami"
  echo " 2 - df"
  echo " 3 - date"
  echo " 4 - cal"
}

# Your loop starts here.
while true; do

  showmenu    # This calls the function above.

  read -p "Enter selection: " option

  case "$option" in
    1) whoami ;;
    2) df ;;
    3) date ;;
    4) cal ;;
    *)
      echo "${RED}Invalid selection. Exiting.${NC}"
      break    # Quit the loop, resuming execution after "done"
      ;;
  esac

  read -p "Enter another command (y/n)?" cont

  case "$cont" in
    N*|n*) break ;;    # Quit the loop, resuming execution after "done"
    *) continue ;;     # Restart the loop. Not strictly necessary here,
                       # since there's nothing left to skip before "done".
  esac

done

echo "I quit."

顺便说一下，这个脚本大部分都不需要bash;您可以在大多数系统上使用/bin/sh运行它。

如何创建一个具有退出和继续选项的while do done脚本？

1 个答案: