所以我至少花了几天时间来解决这个问题。
我想有2个线程的HTTP服务器,每个服务器提供两个不同的IP:端口 我打开一个FF并导航到说:http://196.64.131.250:8001/或http://196.64.131.250:8002,它应该执行GET。
此外,我喜欢我的线程或程序本身在命令行给定持续时间后停止5秒。 我已尽我所能,甚至尝试了SIGAlarm和变量" keepRunning"在持续时间后由第三个线程更改,但我的程序不会停止。请问我做错了什么。
请注意我已对守护进程发表了评论:即(ZhttpThread [1-2] .daemon = True)
如果我不评论它我的线程马上停止。我希望我的HTTP服务器线程继续服务,如果持续时间DUR到期,则程序停止或线程停止。
import SimpleHTTPServer, SocketServer, logging, cgi, sys, signal, threading, time
import subprocess as sub
keepRunning = True
origTime = int(time.time())
class ServerHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
def do_GET(self):
logging.warning("======= GET STARTED =======")
getHdr = self.headers
SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self)
getHdr = self.headers
print(', '.join((getHdr)))
#if ("accept-encoding" in getHdr):
if ("accept-encoding" in (', '.join((getHdr)))):
print ('Test Passed ---------------')
signal.alarm(1)
class threadWithTO(threading.Thread):
def __init__(self, thID, ip, port, timeout):
threading.Thread.__init__(self)
self.ip = ip
self.port = port
self.handler = ServerHandler
self.httpd = SocketServer.TCPServer((self.ip, self.port), self.handler)
def run(self):
print (self.httpd)
#self.httpd.serve_forever()
if (keepRunning == True):
self.httpd.handle_request()
else:
self._stop.set()
def Run(self):
self.start()
def timeHandler(signum, frame):
print('Times up', signum)
sys.exit()
def timeChkr( threadName, dur, t1, t2):
print (origTime)
print ('Begin Timer thread')
while True:
nowTime = int(time.time())
print (nowTime)
delta = nowTime - origTime
if (delta >= dur):
keepRunning = False
t1.stop()
t2.stop()
else:
time.sleep(1)
def main():
#signal.signal(signal.SIGALRM, timeHandler)
#signal.alarm(DUR)
origTime = int(time.time())
ZhttpThread1 = threadWithTO("thread1", I, PORT, DUR)
ZhttpThread2 = threadWithTO("thread2", I, (int(PORT)+1), DUR)
t = threading.Thread(target=timeChkr, args = ("thread3",DUR))
t.daemon = True
t.start()
#ZhttpThread1.daemon = True
#ZhttpThread2.daemon = True
ZhttpThread1.Run()
ZhttpThread2.Run()
答案 0 :(得分:0)
好吧我发现问题在于套接字。我的套接字是打开的,即使我已经尝试过socket.settimeout,我仍然无法让套接字关闭
答案 1 :(得分:0)
感谢安德鲁......我的儿子在我的脑海中引发了这个想法......这是解决方案..
class ServerHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
def do_GET(self):
logging.warning("======= GET STARTED =======")
logging.warning(self.headers)
SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self)
def do_POST(self):
logging.warning("======= POST STARTED =======")
logging.warning(self.headers)
form = cgi.FieldStorage(
fp=self.rfile,
headers=self.headers,
environ={'REQUEST_METHOD':'POST',
'CONTENT_TYPE':self.headers['Content-Type'],
})
logging.warning("======= POST VALUES =======")
print form.list
'''
for item in form.list:
logging.warning(item) '''
logging.warning("\n")
SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self)
class StoppableHTTPServer(BaseHTTPServer.HTTPServer):
def server_bind(self):
BaseHTTPServer.HTTPServer.server_bind(self)
self.socket.settimeout(1)
self.run = True
def get_request(self):
while self.run:
try:
sock, addr = self.socket.accept()
sock.settimeout(None)
return (sock, addr)
except socket.timeout:
pass
def stop(self):
self.run = False
def serve(self):
while self.run:
#print "1"
self.handle_request()
if __name__=="__main__":
if len(sys.argv) < 1:
I = ""
PORT = 8000
DUR = 10
else:
I = sys.argv[1]
PORT = int(sys.argv[2])
DUR = int(sys.argv[3])
#httpd1 = StoppableHTTPServer((I,PORT), SimpleHTTPServer.SimpleHTTPRequestHandler)
#httpd2 = StoppableHTTPServer((I,(int(PORT)+1)), SimpleHTTPServer.SimpleHTTPRequestHandler)
httpd1 = StoppableHTTPServer((I,PORT), ServerHandler)
httpd2 = StoppableHTTPServer((I,(int(PORT)+1)), ServerHandler)
thread.start_new_thread(httpd1.serve, ())
thread.start_new_thread(httpd2.serve, ())
#raw_input("Press <RETURN> to stop server\n")`enter code here`
print '0'
time.sleep(DUR)
print 'Times up Dude'
httpd1.stop()
httpd2.stop()