Question

TL; DR：我有jQuery.myPlugin

$.fn.myPlugin = function(param, callback){
  //...which does some operations to each member of collection
  //obtained by $('.someclass').myPlugin()
  //that are represented with this variable
}

如何在插件完成工作时将 this 变量 - 单节点引用 - 传递给callback？像这样：

$.fn.myPlugin = function(param, callback){
  //...
  //...
  //when job is done:
  callback.call(this);
}
$('.someclass').myPlugin(options, function(arg){ 
  //I need arg to be this variable from plugins definition...
})

请注意，无论我传递给callback.call(somevar)，somevar在执行的匿名回调函数中都不可用。

Answer 1

如果回调肯定是一个功能，你应该尝试

callback(this);

Answer 2

//when job is done:
callback(this);

直接调用回调。或使用

//when job is done: 
callback.call(this, this);

请参阅.call API docs。

jQuery插件：如何将元素引用传递给回调函数？

2 个答案: