Question

我有这些字符串数组：

  string[] BayReplyArray1 = new string[30];
  string[] BayReplyArray2 = new string[30];
  string[] BayReplyArray3 = new string[30];
... up to 10

我想在这样的循环中访问它们：

for (int i = 1; i < 11; i++)
{
    BayReplyArray[i] = "test";
}

它说BayReplyArray在当前上下文中不存在。我可以看出为什么它很困惑，但我怎么能做到这一点？

Answer 1

对此的一个简单解决方案是多维数组。

string[,] BayReplyArrays = new string[10,30]

for(int i = 0; i < 10; i++)
{
    for(int j = 0; j < 30; j++)
    {
        BayReplyArrays[i,j] = "test";
    }
}

这是MSDN多维数组指南：{{3}}

Answer 2

您可以使用以下内容：

const int NumberOfArrays = 10;
const int NumberOfValuesInEachArray = 30;

// array of arrays (could also use a List)
var AllBayReplyArrays = new string[NumberOfArrays][];

// create each nested array
for (var i = 0; i < NumberOfArrays; i++)
{
    AllBayReplyArrays[i] = new string[NumberOfValuesInEachArray];
}

// set values in each array
for (var i = 0; i < NumberOfArrays; i++)
{
    for (var j = 0; j < NumberOfValuesInEachArray; j++)
    {
        // you can write whatever values you like here, I have added the indices to be able to validate the output
        AllBayReplyArrays[i][j] = String.Format("Test {0}-{1}", i, j);
    }
}

// check the values:
Console.WriteLine("The 5th value of the 1st array should be Test 0-4 (for zero based indexes), it is: {0}", AllBayReplyArrays[0][4]);
Console.Read(); //to pause execution

输出结果为：

第一个数组的第5个值应为Test 0-4（基于零索引），它是：测试0-4

在一个班轮中获得相同结果的另一种方法是：

var AllBayReplyArrays = Enumerable.Range(0,9).Select(i => Enumerable.Range(0,29).Select(j => String.Format("Test {0}-{1}", i, j)).ToArray()).ToArray();

您可以在第一个解决方案的底部使用相同的两个测试行来检查它。

Answer 3

除了其他答案，你可以创建一个数组列表然后循环它。

string[] arrString1 = new string[30];
string[] arrString2 = new string[30];
string[] arrString3 = new string[30];

List<string[]> ListOfArrays = new List<string[]>{ arrString1, arrString2, arrString3};


for (int i = 0; i < ListOfArrays.Count; ++i)
{
   string[] CurrentList = ListOfArrays[i];
   for (int i2 = 0; i2 < CurrentList.Count(); ++i2)
   {
       CurrentList[i2] = "Test";
   }
}

Answer 4

感谢所有评论，他们每个人都以某种方式激励我。结果最终使用了锯齿状阵列。

         // declare jagged array with 3 rows
     string[][] jaggedArray = new string[3][];

     // create new arrays in the jagged array and give them a size
     jaggedArray[0] = new string[5];
     jaggedArray[1] = new string[5];
     jaggedArray[2] = new string[5];

     // this assigns values to the first row
     jaggedArray[0][0] = "test1";
     jaggedArray[0][1] = "  test2  ";
     jaggedArray[0][2] = "test3";
     jaggedArray[0][3] = "test4";
     jaggedArray[0][4] = "test5";

     // this assigns values to the second row
     for (int i = 0; i < jaggedArray[1].Length; i++)
     {
        jaggedArray[1][i] = "tt" + i;
     }

     // this assigns values to the third row
     //jaggedArray[2] = new string[3] { "k1", "k2", "k3" };
     string StrTest = "the:quick:brown: fox ";
     char[] delimiters = new char[] { 'u', ':' };
     jaggedArray[2] = StrTest.Split(delimiters);

     // Print out all elements in the jagged array.
     for (int i = 0; i < jaggedArray.Length; i++)
     {
        string[] innerArray = jaggedArray[i];
        for (int j = 0; j < innerArray.Length; j++)
        {
           // this trims whitespace from all elements in the jagged array
           innerArray[j] = innerArray[j].Trim();
           Console.Write(innerArray[j] + " ");
        }
        // this fires after each row in the jagged array
        Console.WriteLine(i);
     }

具有相似名称的多个数组，使用变量访问

4 个答案: