MYSQL 5.6：选择CSV列中的值

Question

我有一个像这样的数据库（Mysql 5.6）：

id | value
--------------------------
1  | "value1;value2;value3"
2  | "value4;value5;value6"

我想发出如下请求：

SELECT id FROM table WHERE 'value5' IS IN value
return --> 2

SQLFiddle：http://sqlfiddle.com/#!9/b5c347

我无法更改数据库架构

Answer 1

如果所有值都不同，您可以使用LIKE：

SELECT id FROM table WHERE value LIKE '%value5%';

请记住，如果你有一些包含另一个的值，它就不会起作用，比如

value2;value3;value56

或使用RegExp，如下所示：

SELECT id FROM table WHERE value REGEXP '(^|[^a-z0-9])value5([^a-z0-9]|$)'

Answer 2

Use LIKE syntax, but use it like this:

SELECT id
FROM table
WHERE
    value LIKE 'value5;%' OR
    value LIKE '%;value5' OR
    value LIKE '%;value5;%' OR
    value LIKE 'value5';

This is a dirty solution, and not possible to index, but should fit your needs (On a smallish table in a reasonable amount of time)

Another solution (If you're sure your values don't contain commas):

SELECT id
FROM table
WHERE
    FIND_IN_SET('value5', REPLACE(value, ';', ',')