Question

这是我的疑问：

SELECT claims.id,
COUNT(CASE WHEN claims.sold_at BETWEEN (now() - INTERVAL '7.day') AND now() END FROM claims) week1
FROM users 
LEFT JOIN claims ON claims.sales_user_id = users.id
WHERE users.office_id = 2

我要做的是加入索赔表，然后计算在特定日期期间售出的数量

此查询出错，但不确定如何正确修复/接近它？

Answer 1

试试这个：

select
        users.id, count(claims.id) as count
    from users
    left join claims on claims.sales_user_id = users.id
        where
            users.office_id = 2 and
            claims.sold_at between (current_timestamp - interval '7' day) and current_timestamp
        group by users.id;

Answer 2

您的查询应如下所示

SELECT claims.id,
       COUNT(CASE
               WHEN claims.sold_at BETWEEN (now() - INTERVAL '7.day') AND now()
               THEN claims.id
               ELSE null END) week1
  FROM users 
  LEFT JOIN claims ON claims.sales_user_id = users.id
 WHERE users.office_id = 2

Answer 3

select
    users.id,
    count(
        claims.sold_at between (now() - interval '7.day') and now()
        or null
    ) week1
from
    users 
    left join
    claims on claims.sales_user_id = users.id
where users.office_id = 2
group by users.id

Answer 4

通常对于这种事情你使用SUM（IF（））。

这样的事情： -

SELECT claims.id,
    SUM(IF(claims.sold_at BETWEEN DATE_SUB(now(), INTERVAL 7 DAY) AND now(), 1, 0)) AS week1
FROM users 
LEFT JOIN claims ON claims.sales_user_id = users.id
WHERE users.office_id = 2

但这本身就没有意义。为什么要将claim.id带回来？没有GROUP BY子句的聚合函数意味着只返回一行，因此返回的claims.id将是随机的。但我希望id是唯一的密钥，所以在这种情况下，它的分组似乎是错误的。

如何使用条件计算左连接的行数

4 个答案: