Question

我想检查用户输入是否在我的数组中。如果不是，则应写入＆＃34;无效输入＆＃34;。线读已经有效。我只想检查一下。但就像我做的那样，它不起作用。我听说我将使用for循环。但是如何？

[...]
char[] menuChars = { 'e', 'E', 'l', 'L', 'k', 'K', 't', 'T', 's', 'S', 'b', 'B' };

if (userKeyPress == !menuChars)
        {
          Console.WriteLine("Please insert a valid char: ");
        }
Console.ReadLine()
[...]

Answer 1

我宁愿将集合类型从数组更改为HashSet<Char>：

  HashSet<Char> menuChars = new HashSet<Char>() {
    'e', 'E', 'l', 'L', 'k', 'K', 't', 'T', 's', 'S', 'b', 'B'
  };

  ...

  Char userKeyPress;

  // and condition check from "if" to "do..while" 
  // in order to repeat asking user until valid character has been provided
  do {
    Console.WriteLine("Please insert a valid char: ");
    // Or this:
    // userKeyPress = Console.Read();
    userKeyPress = Console.ReadKey().KeyChar;
  }
  while (!menuChars.Contains(userKeyPress));

Answer 2

尝试：

menu.setMainPage(...)

Answer 3

你可以试试ethis：

if(menuChars.Contains(userKeyPress))
{
     Console.WriteLine("Found");
}
else
{
   Console.WriteLine("Not Found");
}

或者像这样：

if(Array.IndexOf(menuChars, userKeyPress) > -1)
{
   Console.WriteLine("Found");
}
else
{
   Console.WriteLine("Not Found");
}

检查用户输入是否在我的阵列中

3 个答案: