我正在尝试过滤关系。在我的数据库中,我有奖项和奖项类别。我想只检索特色而非提名奖。
这是我的模特:
class AwardsAwardsCategory(Base):
__tablename__ = 'awards_awards_categories'
id = Column(Text, primary_key=True, default=generate_unique_id)
awards = relationship("Award")
award_id = Column(Text, ForeignKey("awards.id", ondelete='cascade'))
nomination = Column(Boolean)
def __json__(self, request):
return {
"id": self.id,
"nomination": self.nomination
}
class Award(Base):
__tablename__ = 'awards'
id = Column(Text, primary_key=True, default=generate_unique_id)
type = Column(Text)
featured = Column(Integer)
awards = relationship("AwardsAwardsCategory", lazy='joined')
def __json__(self, request):
return {
"id": self.id,
"type": self.type,
"number_of_awards": len(self.awards),
"featured": self.featured,
}
这是我的电话:
query = self.session.query(Award)
query = query.join(AwardsAwardsCategory.awards)
query = query.filter(Award.featured != 0)
query = query.filter(AwardsAwardsCategory.nomination != True)
q_results = query.all()
这导致以下查询:
SELECT awards.id AS awards_id, awards.type AS awards_type, awards.featured AS awards_featured, awards_awards_categories_1.id AS awards_awards_categories_1_id, awards_awards_categories_1.award_id AS awards_awards_categories_1_award_id, awards_awards_categories_1.nomination AS awards_awards_categories_1_nomination
FROM awards_awards_categories JOIN awards ON awards.id = awards_awards_categories.award_id LEFT OUTER JOIN awards_awards_categories AS awards_awards_categories_1 ON awards.id = awards_awards_categories_1.award_id
WHERE awards.featured != 0 AND awards_awards_categories.nomination != true
除了WHERE子句缺少条件外几乎正确:
AND awards_awards_categories_1.nomination != true
如何更改我的代码,以便将最后一个条件添加到WHERE子句中。
答案 0 :(得分:0)
我最终过滤了应用层上的提名。它很讨厌,但它确实有效。
query = self.session.query(Award)
query = query.join(AwardsAwardsCategory.awards)
query = query.filter(Award.featured != 0)
query = query.filter(AwardsAwardsCategory.nomination != True)
q_results = query.all()
# remove all objects from the session in order to keep them in the db.
self.session.expunge_all()
for award_category in q_results:
# keep a separate list of the awards, in order to keep the iteration going as desired
awards = list(award_category)
for award in award_category.awards:
if award.nomination:
awards.remove(award)
def __json__(self, request):
return {
"id": self.id,
"type": self.type,
"number_of_awards": self.number_of_awards,
"featured": self.featured,
}
award_category.number_of_awards = len(awards)
award_category.__json__ = types.MethodType( __json__, a )
如果有人知道如何在SQLAlchemy中做得更好,请告诉我!