我有以下两个查询,我想组合成一个日期为第一列的查询。我遇到的问题是子查询的条件不同,第二个查询可能没有每个月的值。我一直在不同的页面上运行它们,因此两者的AS num_custs是相同的。
我用SQL尝试过几个不同的东西但到目前为止都失败了。我最初的想法是在SQL中使用UNION但是没有用。我认为我在正确的轨道上尝试用SQL而不是PHP。
第一个问题是我应该使用哪个SQL命令来实现这个目标?
希望一切都有意义。
查询1:
SELECT * , COUNT( entity_id ) AS num_custs
FROM (
SELECT e. * , e.created_at AS abc123, o.status, o.total_invoiced, o.shipping_description, o.subtotal_incl_tax, MAX( o.created_at ) AS last_order_date
FROM mg_customer_entity AS e
LEFT JOIN mg_sales_flat_order AS o ON o.customer_id = e.entity_id
WHERE e.entity_type_id = '1'
AND o.status NOT LIKE 'canceled'
AND o.status NOT LIKE 'closed'
AND o.status NOT LIKE 'fraud'
AND o.status NOT LIKE 'holded'
AND o.status NOT LIKE 'paypal_canceled_reversal'
AND e.store_id
BETWEEN 1
AND 2
AND o.total_invoiced IS NOT NULL
AND o.subtotal_incl_tax IS NOT NULL
GROUP BY e.entity_id
HAVING last_order_date IS NOT NULL
)sub_query
GROUP BY YEAR( abc123 ) , MONTH( abc123 )
ORDER BY abc123 DESC
查询2:
SELECT * , COUNT( entity_id ) AS num_custs
FROM (
SELECT e. * , e.created_at AS abc123, o.status, o.total_invoiced, o.shipping_description, o.subtotal_incl_tax, MAX( o.created_at ) AS last_order_date
FROM mg_customer_entity AS e
LEFT JOIN mg_sales_flat_order AS o ON o.customer_id = e.entity_id
WHERE e.entity_type_id = '1'
AND o.status NOT LIKE 'canceled'
AND o.status NOT LIKE 'closed'
AND o.status NOT LIKE 'fraud'
AND o.status NOT LIKE 'holded'
AND o.status NOT LIKE 'paypal_canceled_reversal'
AND e.store_id
BETWEEN 1
AND 2
AND o.total_invoiced IS NOT NULL
AND o.subtotal_incl_tax IS NOT NULL
GROUP BY e.entity_id
HAVING last_order_date >= DATE_SUB( CURDATE( ) , INTERVAL 91 DAY )
AND last_order_date IS NOT NULL
)sub_query
GROUP BY YEAR( abc123 ) , MONTH( abc123 )
ORDER BY abc123 DESC
答案 0 :(得分:0)
您提到您希望将日期作为第一个结果,您可以指定所有字段或只是将其添加到前面。
如果您使用PHP构建查询,则可以轻松注入额外条件。
条件将插入"%s"位于sprintf function。
// set $limit_order_date depending on the page
$having = '';
if ( true === $limit_order_date ) {
$having = 'AND last_order_date >= DATE_SUB( CURDATE( ) , INTERVAL 91 DAY )';
}
$sql = sprintf("
SELECT abc123,
* ,
COUNT( entity_id ) AS num_custs
FROM (
SELECT e. *,
e.created_at AS abc123,
o.status,
o.total_invoiced,
o.shipping_description,
o.subtotal_incl_tax,
MAX( o.created_at ) AS last_order_date
FROM mg_customer_entity AS e
LEFT JOIN mg_sales_flat_order AS o
ON o.customer_id = e.entity_id
WHERE e.entity_type_id = '1'
AND o.status NOT LIKE 'canceled'
AND o.status NOT LIKE 'closed'
AND o.status NOT LIKE 'fraud'
AND o.status NOT LIKE 'holded'
AND o.status NOT LIKE 'paypal_canceled_reversal'
AND e.store_id BETWEEN 1 AND 2
AND o.total_invoiced IS NOT NULL
AND o.subtotal_incl_tax IS NOT NULL
GROUP BY e.entity_id
HAVING last_order_date IS NOT NULL %s
)sub_query
GROUP BY YEAR( abc123 ),
MONTH( abc123 )
ORDER BY abc123 DESC",
$having
);
我希望我正确地解释你的问题。