Question

我是SQL Server的初学者

我在数据库医院有三个表

PatientFiles
其他服务
PatientDeposit

显示结果的两个查询

查询第一名。显示PatientFilesID，TotalOtherServices

SELECT pf.ID AS PatientFileID, SUM(os.Quantum * os.Price) AS TotalOtherServices
FROM PatientsFiles pf INNER JOIN OtherServices os ON pf.ID = os.Patient_File_ID 
WHERE pf.ID = '14'
GROUP BY pf.ID

这是真实的结果

    PatientFileID  | TotalOtherServices
        14                194.00

查询第二个。显示PatientFilesID，TotalPatientDeposit

SELECT pd.Patient_File_ID AS PatientFileID, SUM(pd.Deposit) AS TotalPatientDeposit
FROM PatientsDeposits pd
WHERE pd.Patient_File_ID = '14'
GROUP BY pd.Patient_File_ID

这是真实的结果

    PatientFileID | TotalPatientDeposit
        14               450.00

我非常厌倦混合两个查询

SELECT pf.ID AS PatientFileID, SUM(os.Quantum * os.Price) AS TotalOtherServices, 
SUM(pd.Deposit) AS TotalPatientDeposit
FROM PatientsFiles pf
INNER JOIN OtherServices os ON pf.ID = os.Patient_File_ID  
INNER JOIN PatientsDeposits pd ON pf.ID = pd.Patient_File_ID
WHERE pf.ID = '14'
GROUP BY pf.ID

这是错误的结果

    PatientFileID  | TotalOtherServices | TotalPatientDeposit
         14                  582.00         1350.00

感谢您提前帮助我

Answer 1

Select pf.ID as PatientFileID,
    os.TotalOtherServices,
    pd.TotalDeposit
From PatientFiles pf
    Left Join
 (Select Patient_File_ID as PatientfileID, SUM(os.Quantum * os.Price) AS TotalOtherServices
  From OtherServices Group By Patient_File_ID) os on pf.PatientFileID = os.PatientFileID
    Left Join
 (Select Patient_File_ID AS PatientFileID, SUM(Deposit) AS TotalPatientDeposit
  From PatientsDeposits Group By Patient_File_ID) pd on pf.PatientFileID = pd.PatientFileID

Answer 2

快速浏览一下，看起来价值是预期值的3倍（194 * 3 = 582,450 * 3 = 1350）。

此外，在您的第二个查询中，您没有使用INNER JOIN。

SELECT pf.ID AS PatientFileID, 
SUM(pd.Deposit) AS TotalPatientDeposit
FROM PatientsFiles pf INNER JOIN PatientsDeposits pd
ON pf.ID = pd.Patient_File_ID
WHERE pd.Patient_File_ID = '14'
GROUP BY pd.Patient_File_ID

我知道这不是答案＆amp;更多应该检查的事情。

SQL Server 2005一个查询计算两个表

2 个答案: